Rotational Motion

Learning Objectives

  • Understand the analogies between linear and angular kinematics.
  • Define and apply concepts of torque and moment of inertia.
  • State and apply Newton's Second Law for rotational motion.
  • Calculate rotational kinetic energy and apply work-energy principles to rolling motion.
  • Define angular momentum and apply the principle of conservation of angular momentum.

Everything we have learned about straight-line (translational) motion has a direct analogy in rotational motion. This is crucial for analyzing spinning gears, turbines, and the stability of structures. While we often model objects as simple point masses moving in straight lines, the real world is filled with spinning, twisting, and rotating bodies. From the massive turbines generating our electricity to the microscopic gears in a watch, rotational motion is everywhere. Fortunately, the mathematical framework we built for linear motion maps perfectly onto rotational motion through a set of elegant analogies.

Angular Kinematics

Angular Position (θ\theta)

The angle of a rotating body relative to a reference line. It is measured in radians (rad), where 2π rad=360=1 revolution2\pi \text{ rad} = 360^\circ = 1 \text{ revolution}.

Angular Position Equation

Relates angular position, arc length, and radius.

θ=sr\theta = \frac{s}{r}

Variables

SymbolDescriptionUnit
θ\thetaAngular positionrad
ssArc lengthm
rrRadiusm

Angular Velocity (ω\omega)

The rate of change of angular position. It tells us how fast an object is spinning.

Angular Velocity Equations

Average and instantaneous angular velocity.

ωavg=ΔθΔt\omega_{avg} = \frac{\Delta\theta}{\Delta t}ω(t)=dθdt\omega(t) = \frac{d\theta}{dt}

Variables

SymbolDescriptionUnit
ω\omegaAngular velocityrad/s
Δθ\Delta\thetaChange in angular positionrad
Δt\Delta tTime intervals

Angular Acceleration (α\alpha)

The rate of change of angular velocity.

Angular Acceleration Equations

Average and instantaneous angular acceleration.

αavg=ΔωΔt\alpha_{avg} = \frac{\Delta\omega}{\Delta t}α(t)=dωdt=d2θdt2\alpha(t) = \frac{d\omega}{dt} = \frac{d^2\theta}{dt^2}

Variables

SymbolDescriptionUnit
α\alphaAngular accelerationrad/s2rad/s^2
Δω\Delta\omegaChange in angular velocityrad/s
Δt\Delta tTime intervals

The Analogies

The Analogies Concepts

Because the calculus relationships between position, velocity, and acceleration are identical in both linear and rotational regimes, the equations of motion for constant angular acceleration are identical in form to the "Big Four" linear equations.

Kinematic Analogies

Linear QuantityRotational QuantityRelation (v=rωv = r\omega)
Position (xx)Angle (θ\theta)s=rθs = r\theta
Velocity (vv)Angular Velocity (ω\omega)v=rωv = r\omega
Tangential Accel (ata_t)Angular Accel (α\alpha)at=rαa_t = r\alpha

Constant Acceleration Equations:

  • ωf=ωi+αt\omega_f = \omega_i + \alpha t
  • Δθ=ωit+12αt2\Delta\theta = \omega_i t + \frac{1}{2}\alpha t^2
  • ωf2=ωi2+2αΔθ\omega_f^2 = \omega_i^2 + 2\alpha\Delta\theta
  • Δθ=(ωi+ωf2)t\Delta\theta = \left(\frac{\omega_i + \omega_f}{2}\right)t

Right-Hand Rule

The vector direction of ω\vec{\omega} and α\vec{\alpha} is determined by the Right-Hand Rule. Curl the fingers of your right hand in the direction of rotation; your thumb points along the axis of rotation in the direction of the angular velocity vector.

Interactive Simulation

Use this rotational kinematics model to connect θ\theta, ω\omega, and α\alpha with the constant-acceleration equations.

Interactive Physics Simulation

Rotational Kinematics & Acceleration Vector Simulator

Study the motion of a particle rotating on a disk. Observe how physical tangential and centripetal acceleration vector components scale at radius R.

3.0 rad/s
0.8 rad/s²
1.5 m
4.0 s
Constant Acceleration Formulas
Final Velocity:ω=ω0+αt\omega = \omega_0 + \alpha t
Displacement:θ=ω0t+12αt2\theta = \omega_0 t + \frac{1}{2}\alpha t^2
Linear Vector Magnitudes:ac=ω2Ra_c = \omega^2 R , at=αRa_t = \alpha R

Note that centripetal acceleration increases with the square of speed, while tangential acceleration remains constant under constant $\alpha$.

Angular Velocity (ω)
6.20 rad/s
Angular displacement (θ)
18.40 rad
Centripetal Accel. (ac)
57.66 m/s²
Tangential Accel. (at)
1.20 m/s²

Rotational Dynamics

Rotational Dynamics Concepts

To cause a change in linear motion, we apply a force (FF). To cause a change in rotational motion, we apply a torque (τ\tau).

Torque (τ\vec{\tau})

The rotational equivalent of force; a measure of how much a force acting on an object causes that object to rotate. It is the cross product of the position vector (from the axis of rotation to the point of force application) and the force vector.

Torque Equation

Vector cross product definition of torque.

τ=r×F\vec{\tau} = \vec{r} \times \vec{F}

Variables

SymbolDescriptionUnit
τ\vec{\tau}Torque vectorNmN\cdot m
r\vec{r}Position vector from axism
F\vec{F}Applied force vectorN

Torque Magnitude Equation

Magnitude of torque using lever arm distance.

τ=rFsinϕ=Fd|\vec{\tau}| = r F \sin\phi = F d

Variables

SymbolDescriptionUnit
τ|\vec{\tau}|Magnitude of torqueNmN\cdot m
rrDistance from axis to force applicationm
FFMagnitude of applied forceN
ϕ\phiAngle between position and force vectorsrad
ddLever arm distancem

Moment of Inertia (II)

Moment of Inertia (II)

The rotational analog to mass, which measures an object's resistance to changes in its rotation. It depends on how the mass is distributed relative to the specific axis of rotation.

Moment of Inertia for Discrete Masses

Calculates moment of inertia for a system of point masses.

I=miri2I = \sum m_i r_i^2

Variables

SymbolDescriptionUnit
IIMoment of inertiakgm2kg\cdot m^2
mim_iMass of particle ikg
rir_iDistance of particle i from axism

Moment of Inertia for Continuous Bodies

Calculates moment of inertia for a continuous solid body.

I=r2dm=ρr2dVI = \int r^2 \, dm = \int \rho r^2 \, dV

Variables

SymbolDescriptionUnit
IIMoment of inertiakgm2kg\cdot m^2
rrDistance from axism
dmdmInfinitesimal mass elementkg
ρ\rhoDensity of the bodykg/m3kg/m^3
dVdVInfinitesimal volume elementm3m^3

Common Moments of Inertia

Parallel-Axis Theorem

Finds moment of inertia around an axis parallel to the center of mass axis.

I=Icm+Md2I = I_{cm} + Md^2

Variables

SymbolDescriptionUnit
IIMoment of inertia about parallel axiskgm2kg\cdot m^2
IcmI_{cm}Moment of inertia about center of masskgm2kg\cdot m^2
MMTotal masskg
ddDistance between parallel axesm

Interactive Simulation

Use this inertia model to compare how mass distribution changes resistance to angular acceleration.

Interactive Physics Simulation

Moment Of Rotational Inertia Simulator

Explore how mass and shape distribution affect resistance to rotation. Apply a tangential force to generate torque and angular acceleration.

5 kg
1.2 m
15 N
Inertia Equation for Profile
I=12MR2I = \frac{1}{2} M R^2

A solid cylinder / disk has its mass evenly distributed from the center axle out to the radius R. More mass distributed far from the center yields a larger moment of inertia ($I$).

Moment of Inertia (I)
3.60 kg·m²
Applied Torque (τ = F·R)
18.00 N·m
Angular Accel. (α = τ/I)
5.00 rad/s²
Angular Velocity (ω)
0.00 rad/s

Newton's Second Law for Rotation

Newton's Second Law for Rotation Concepts

With torque and moment of inertia defined, we can state the rotational equivalent of F=maF=ma. The net torque on a rigid body is equal to its moment of inertia multiplied by its angular acceleration.

Newton's Second Law for Rotation

Relates net torque, moment of inertia, and angular acceleration.

Στ=Iα\Sigma \vec{\tau} = I \vec{\alpha}

Variables

SymbolDescriptionUnit
Στ\Sigma \vec{\tau}Net torqueNmN\cdot m
IIMoment of inertiakgm2kg\cdot m^2
α\vec{\alpha}Angular acceleration vectorrad/s2rad/s^2

Rotational Energy and Work

Rotational Energy and Work Concepts

A spinning object has kinetic energy, even if its center of mass is stationary.

Rotational Kinetic Energy (KRK_R)

The kinetic energy possessed by an object due to its rotational motion.

Rotational Kinetic Energy Equation

Calculates kinetic energy from rotational motion.

KR=12Iω2K_R = \frac{1}{2}I\omega^2

Variables

SymbolDescriptionUnit
KRK_RRotational kinetic energyJ
IIMoment of inertiakgm2kg\cdot m^2
ω\omegaAngular velocityrad/s

Rolling Without Slipping

Rolling Without Slipping Concepts

When a wheel or sphere rolls across a surface without slipping, there is a strict relationship between its translational velocity (vcmv_{cm}) and its angular velocity (ω\omega). Because it is both translating and rotating, its total kinetic energy is the sum of its translational and rotational kinetic energies: Ktotal=12Mvcm2+12Icmω2K_{total} = \frac{1}{2}Mv_{cm}^2 + \frac{1}{2}I_{cm}\omega^2.

Rolling Translational Velocity

Relates center of mass velocity to angular velocity.

vcm=Rωv_{cm} = R \omega

Variables

SymbolDescriptionUnit
vcmv_{cm}Velocity of the center of massm/s
RRRadius of the rolling objectm
ω\omegaAngular velocityrad/s

Work-Energy Theorem for Rotation

The work done by a torque τ\tau rotating an object through an angle Δθ\Delta\theta is equal to the change in rotational kinetic energy.

Work Done by Torque

Calculates work done by applying torque over an angle.

W=τdθW = \int \tau \, d\theta

Variables

SymbolDescriptionUnit
WWWork doneJ
τ\tauTorqueNmN\cdot m
dθd\thetaInfinitesimal angular displacementrad

Angular Momentum (LL)

Angular Momentum (L\vec{L})

The rotational analog to linear momentum (p=mvp=mv). For a rigid body rotating about a fixed axis of symmetry, it is the product of moment of inertia and angular velocity.

Angular Momentum of a Point Particle

Angular momentum for a point particle relative to an origin.

L=r×p\vec{L} = \vec{r} \times \vec{p}

Variables

SymbolDescriptionUnit
L\vec{L}Angular momentum vectorkgm2/skg\cdot m^2/s
r\vec{r}Position vectorm
p\vec{p}Linear momentum vectorkgm/skg\cdot m/s

Angular Momentum of a Rigid Body

Angular momentum for a rigid body rotating around a fixed axis.

L=Iω\vec{L} = I\vec{\omega}

Variables

SymbolDescriptionUnit
L\vec{L}Angular momentum vectorkgm2/skg\cdot m^2/s
IIMoment of inertiakgm2kg\cdot m^2
ω\vec{\omega}Angular velocity vectorrad/s

Conservation of Angular Momentum

Just as ΣF=dp/dt\Sigma F = dp/dt, the net torque equals the rate of change of angular momentum: Στ=dL/dt\Sigma \vec{\tau} = d\vec{L}/dt.

Conservation Principle

Conservation of Angular Momentum: If the net external torque on a system is zero (Στext=0\Sigma \vec{\tau}_{ext} = 0), the total angular momentum of the system is conserved (Li=Lf\vec{L}_i = \vec{L}_f). This explains why a figure skater spins faster when they pull their arms in (decreasing II must increase ω\omega to keep L=IωL=I\omega constant).

Interactive Simulation

Use this angular momentum model to see why pulling mass inward makes angular speed rise when external torque is negligible.

Interactive Physics Simulation

Angular Momentum Skater Simulator

Pull the rotating masses inward or outward. When friction and external torque are neglected, moment of inertia decreases, causing spin velocity to increase.

1.30 m
0.70 m
2.0 kg·m²
2.5 rad/s
Governing Laws
Moment of Inertia
I=Ibody+2mr2I = I_{body} + 2m \cdot r^2
Conservation of Momentum
L=Iiωi=IfωfL = I_i \cdot \omega_i = I_f \cdot \omega_f
Rotating skater demonstrating the conservation of angular momentumOrbit expands as spin speed (ω) increases
Angular Momentum (L)
17.68 kg·m²/s
Current Angular Speed (ω)
5.09 rad/s

Parallel-Axis Theorem in Practice

Calculating Complex Inertia

The Parallel-Axis Theorem is not just an abstract concept; it is vital for calculating the moment of inertia of complex, composite engineering shapes (like I-beams or rotating eccentric cams) where the axis of rotation does not pass through the center of mass of every individual component.

By breaking a complex shape into simple geometric parts (rectangles, circles), finding their individual moments of inertia about their own centers of mass, and then using the Parallel-Axis Theorem (I=Icm+Md2I = I_{cm} + Md^2) to shift those moments to the global axis of rotation, engineers can analyze the rotational dynamics of virtually any rigid body.

Key Takeaways
  • Rotational kinematics equations (θ,ω,α\theta, \omega, \alpha) are exactly analogous to linear equations (x,v,ax, v, a).
  • Torque (τ=r×F\vec{\tau} = \vec{r} \times \vec{F}) is the rotational analog to force, causing angular acceleration.
  • Moment of Inertia (I=mr2I = \sum mr^2) is the rotational analog to mass, representing resistance to angular acceleration. It depends on mass distribution.
  • Newton's Second Law for rotation is Στ=Iα\Sigma \vec{\tau} = I \vec{\alpha}.
  • A spinning object possesses Rotational Kinetic Energy (KR=12Iω2K_R = \frac{1}{2}I\omega^2).
  • Angular Momentum (L=Iω\vec{L} = I\vec{\omega}) is conserved if the net external torque is zero.