Rotational Motion

Learning Objectives

  • Understand the analogies between linear and angular kinematics.
  • Define and apply concepts of torque and moment of inertia.
  • State and apply Newton's Second Law for rotational motion.
  • Calculate rotational kinetic energy and apply work-energy principles to rolling motion.
  • Define angular momentum and apply the principle of conservation of angular momentum.
  • Apply the parallel-axis theorem and relate the physical radius of a body to its rendered and calculated rotational geometry.

Everything we have learned about straight-line (translational) motion has a direct analogy in rotational motion. This is crucial for analyzing spinning gears, turbines, and the stability of structures. While we often model objects as simple point masses moving in straight lines, the real world is filled with spinning, twisting, and rotating bodies. From the massive turbines generating our electricity to the microscopic gears in a watch, rotational motion is everywhere. Fortunately, the mathematical framework we built for linear motion maps perfectly onto rotational motion through a set of elegant analogies.

Angular Kinematics

Angular Position (θ\theta)

The angle of a rotating body relative to a reference line. It is measured in radians (rad), where 2π rad=360∘=1 revolution2\pi \text{ rad} = 360^\circ = 1 \text{ revolution}.

Angular Position Equation

Relates angular position, arc length, and radius.

θ=sr\theta = \frac{s}{r}

Variables

SymbolDescriptionUnit
θ\thetaAngular positionrad
ssArc lengthm
rrRadiusm

Angular Velocity (ω\omega)

The rate of change of angular position. It tells us how fast an object is spinning.

Angular Velocity Equations

Average and instantaneous angular velocity.

ωavg=ΔθΔt\omega_{avg} = \frac{\Delta\theta}{\Delta t}ω(t)=dθdt\omega(t) = \frac{d\theta}{dt}

Variables

SymbolDescriptionUnit
ω\omegaAngular velocityrad/s
Δθ\Delta\thetaChange in angular positionrad
Δt\Delta tTime intervals

Angular Acceleration (α\alpha)

The rate of change of angular velocity.

Angular Acceleration Equations

Average and instantaneous angular acceleration.

αavg=ΔωΔt\alpha_{avg} = \frac{\Delta\omega}{\Delta t}α(t)=dωdt=d2θdt2\alpha(t) = \frac{d\omega}{dt} = \frac{d^2\theta}{dt^2}

Variables

SymbolDescriptionUnit
α\alphaAngular accelerationrad/s2rad/s^2
Δω\Delta\omegaChange in angular velocityrad/s
Δt\Delta tTime intervals

The Analogies

The Analogies Concepts

Because the calculus relationships between position, velocity, and acceleration are identical in both linear and rotational regimes, the equations of motion for constant angular acceleration are identical in form to the "Big Four" linear equations.

Kinematic Analogies

Linear QuantityRotational QuantityRelation (v=rωv = r\omega)
Position (xx)Angle (θ\theta)s=rθs = r\theta
Velocity (vv)Angular Velocity (ω\omega)v=rωv = r\omega
Tangential Accel (ata_t)Angular Accel (α\alpha)at=rαa_t = r\alpha

Constant Acceleration Equations:

  • ωf=ωi+αt\omega_f = \omega_i + \alpha t
  • Δθ=ωit+12αt2\Delta\theta = \omega_i t + \frac{1}{2}\alpha t^2
  • ωf2=ωi2+2αΔθ\omega_f^2 = \omega_i^2 + 2\alpha\Delta\theta
  • Δθ=(ωi+ωf2)t\Delta\theta = \left(\frac{\omega_i + \omega_f}{2}\right)t

Right-Hand Rule

The vector direction of ω⃗\vec{\omega} and α⃗\vec{\alpha} is determined by the Right-Hand Rule. Curl the fingers of your right hand in the direction of rotation; your thumb points along the axis of rotation in the direction of the angular velocity vector.

Interactive Simulation

Use this rotational kinematics model to connect θ\theta, ω\omega, and α\alpha with the constant-acceleration equations.

Rotational Kinematics Simulator

Concept and model scope

Use one canonical physical radius R. Changing R resizes the rotating body itself, keeps the tracked point on the rim, and updates vₜ = ωR, aₜ = αR, and a_c = ω²R from the same geometry. Positive angular quantities are counterclockwise.

Model scope: Use the displayed units and idealizations, then verify the governing balance or compatibility equation before interpreting the result.

R = 1.50 m
Initial angular velocity (ω₀)

Initial angular velocity (ω₀)

Initial angular velocity (ω₀) is an adjustable engineering parameter. The displayed result and geometry should update directly from this value.

Range: -6.00–8.00 rad/s. Step: 0.25 rad/s.

3.00 rad/s
Angular acceleration (α)

Angular acceleration (α)

Angular acceleration (α) is an adjustable engineering parameter. The displayed result and geometry should update directly from this value.

Range: -3.0–3.0 rad/s². Step: 0.1 rad/s².

0.8 rad/s²
Elapsed time (t)

Elapsed time (t)

Elapsed time (t) is an adjustable engineering parameter. The displayed result and geometry should update directly from this value.

Range: 0.0–8.0 s. Step: 0.1 s.

4.0 s
Physical disk radius (R)

Physical disk radius (R)

Physical disk radius (R) is an adjustable engineering parameter. The displayed result and geometry should update directly from this value.

Range: 0.5–2.0 m. Step: 0.1 m.

1.5 m

Constant-α model

ω = ω₀ + αt

θ = ω₀t + ½αt²

At the rim: vₜ = ωR, aₜ = αR, a_c = ω²R.

A vector is omitted when its physical magnitude is zero; the diagram never shows a minimum-length “fake” acceleration arrow.

vₜaₜa_cR = 1.50 m
Angular displacement θ
18.40 rad
Angular velocity ω
6.20 rad/s
Tangential velocity vₜ
9.30 m/s
Net acceleration magnitude
57.67 m/s²
Centripetal acceleration a_c
57.66 m/s²
Tangential acceleration aₜ
1.20 m/s²

Rotational Dynamics

Rotational Dynamics Concepts

To cause a change in linear motion, we apply a force (FF). To cause a change in rotational motion, we apply a torque (τ\tau).

Torque (τ⃗\vec{\tau})

The rotational equivalent of force; a measure of how much a force acting on an object causes that object to rotate. It is the cross product of the position vector (from the axis of rotation to the point of force application) and the force vector.

Torque Equation

Vector cross product definition of torque.

τ⃗=r⃗×F⃗\vec{\tau} = \vec{r} \times \vec{F}

Variables

SymbolDescriptionUnit
τ⃗\vec{\tau}Torque vectorN⋅mN\cdot m
r⃗\vec{r}Position vector from axism
F⃗\vec{F}Applied force vectorN

Torque Magnitude Equation

Magnitude of torque using lever arm distance.

∣τ⃗∣=rFsin⁡ϕ=Fd|\vec{\tau}| = r F \sin\phi = F d

Variables

SymbolDescriptionUnit
∣τ⃗∣|\vec{\tau}|Magnitude of torqueN⋅mN\cdot m
rrDistance from axis to force applicationm
FFMagnitude of applied forceN
ϕ\phiAngle between position and force vectorsrad
ddLever arm distancem
Torque and the Perpendicular Lever Arm

Only the component of force perpendicular to the position vector contributes to torque magnitude.

Wrench showing position vector, oblique force, and perpendicular lever arm

Moment of Inertia (II)

Moment of Inertia (II)

The rotational analog to mass, which measures an object's resistance to changes in its rotation. It depends on how the mass is distributed relative to the specific axis of rotation.

Moment of Inertia for Discrete Masses

Calculates moment of inertia for a system of point masses.

I=∑miri2I = \sum m_i r_i^2

Variables

SymbolDescriptionUnit
IIMoment of inertiakg⋅m2kg\cdot m^2
mim_iMass of particle ikg
rir_iDistance of particle i from axism

Moment of Inertia for Continuous Bodies

Calculates moment of inertia for a continuous solid body.

I=∫r2 dm=∫ρr2 dVI = \int r^2 \, dm = \int \rho r^2 \, dV

Variables

SymbolDescriptionUnit
IIMoment of inertiakg⋅m2kg\cdot m^2
rrDistance from axism
dmdmInfinitesimal mass elementkg
ρ\rhoDensity of the bodykg/m3kg/m^3
dVdVInfinitesimal volume elementm3m^3

Common Moments of Inertia

  • Solid Cylinder or Disk (axis through center): I=12MR2I = \frac{1}{2}MR^2
  • Hoop or Thin Cylindrical Shell (axis through center): I=MR2I = MR^2
  • Solid Sphere (axis through center): I=25MR2I = \frac{2}{5}MR^2
  • Thin Rod (axis through center): I=112ML2I = \frac{1}{12}ML^2
  • Thin Rod (axis through end): I=13ML2I = \frac{1}{3}ML^2

Parallel-Axis Theorem

Finds moment of inertia around an axis parallel to the center of mass axis.

I=Icm+Md2I = I_{cm} + Md^2

Variables

SymbolDescriptionUnit
IIMoment of inertia about parallel axiskg⋅m2kg\cdot m^2
IcmI_{cm}Moment of inertia about center of masskg⋅m2kg\cdot m^2
MMTotal masskg
ddDistance between parallel axesm
Parallel-Axis Geometry

Moving the reference axis a distance d from the center-of-mass axis adds Md squared to the moment of inertia.

Body with centroidal axis and a parallel shifted axis separated by distance d

Interactive Simulation

Use this inertia model to compare how mass distribution changes resistance to angular acceleration. Its radius control represents the same physical outer radius used in both the geometry and inertia equations.

Moment Of Rotational Inertia Simulator

Concept and model scope

Compare canonical rigid-body inertia models using one physical radius R. The rendered body, the tangential-force lever arm, and every inertia/torque calculation use the same R; interior markers are deterministic visual guides, not individual point masses.

Model scope: Use the displayed units and idealizations, then verify the governing balance or compatibility equation before interpreting the result.

Mass (M)

Mass (M)

Mass (M) is an adjustable engineering parameter. The displayed result and geometry should update directly from this value.

Range: 1–20 kg. Step: 1 kg.

5 kg
Radius (R)

Radius (R)

Radius (R) is an adjustable engineering parameter. The displayed result and geometry should update directly from this value.

Range: 0.4–2.0 m. Step: 0.1 m.

1.2 m
Applied Tangent Force (F)

Applied Tangent Force (F)

Applied Tangent Force (F) is an adjustable engineering parameter. The displayed result and geometry should update directly from this value.

Range: 0–50 N. Step: 1 N.

15 N
Inertia Equation for Profile
I=12MR2I = \frac{1}{2} M R^2

A solid cylinder / disk has its mass evenly distributed from the center axle out to the radius R. More mass distributed far from the center yields a larger moment of inertia II.

Moment of Inertia (I)
3.60 kg·m²
Applied Torque (τ = F·R)
18.00 N·m
Angular Accel. (α = τ/I)
5.00 rad/s²
Angular Velocity (ω)
0.00 rad/s

Newton's Second Law for Rotation

Newton's Second Law for Rotation Concepts

With torque and moment of inertia defined, we can state the rotational equivalent of F=maF=ma. The net torque on a rigid body is equal to its moment of inertia multiplied by its angular acceleration.

Newton's Second Law for Rotation

Relates net torque, moment of inertia, and angular acceleration.

Στ⃗=Iα⃗\Sigma \vec{\tau} = I \vec{\alpha}

Variables

SymbolDescriptionUnit
Στ⃗\Sigma \vec{\tau}Net torqueN⋅mN\cdot m
IIMoment of inertiakg⋅m2kg\cdot m^2
α⃗\vec{\alpha}Angular acceleration vectorrad/s2rad/s^2

Rotational Energy and Work

Rotational Energy and Work Concepts

A spinning object has kinetic energy, even if its center of mass is stationary.

Rotational Kinetic Energy (KRK_R)

The kinetic energy possessed by an object due to its rotational motion.

Rotational Kinetic Energy Equation

Calculates kinetic energy from rotational motion.

KR=12Iω2K_R = \frac{1}{2}I\omega^2

Variables

SymbolDescriptionUnit
KRK_RRotational kinetic energyJ
IIMoment of inertiakg⋅m2kg\cdot m^2
ω\omegaAngular velocityrad/s

Rolling Without Slipping

Rolling Without Slipping Concepts

When a wheel or sphere rolls across a surface without slipping, there is a strict relationship between its translational velocity (vcmv_{cm}) and its angular velocity (ω\omega). Because it is both translating and rotating, its total kinetic energy is the sum of its translational and rotational kinetic energies: Ktotal=12Mvcm2+12Icmω2K_{total} = \frac{1}{2}Mv_{cm}^2 + \frac{1}{2}I_{cm}\omega^2.

Rolling Translational Velocity

Relates center of mass velocity to angular velocity.

vcm=Rωv_{cm} = R \omega

Variables

SymbolDescriptionUnit
vcmv_{cm}Velocity of the center of massm/s
RRRadius of the rolling objectm
ω\omegaAngular velocityrad/s
Rolling without Slipping and Energy Partition

For pure rolling, v at the center equals R omega, and total kinetic energy contains both translational and rotational terms.

Wheel rolling without slipping with translational velocity, angular velocity, radius, and kinetic-energy partition

Work-Energy Theorem for Rotation

The work done by a torque τ\tau rotating an object through an angle Δθ\Delta\theta is equal to the change in rotational kinetic energy.

Work Done by Torque

Calculates work done by applying torque over an angle.

W=∫τ dθW = \int \tau \, d\theta

Variables

SymbolDescriptionUnit
WWWork doneJ
τ\tauTorqueN⋅mN\cdot m
dθd\thetaInfinitesimal angular displacementrad

Angular Momentum (LL)

Angular Momentum (L⃗\vec{L})

The rotational analog to linear momentum (p=mvp=mv). For a rigid body rotating about a fixed axis of symmetry, it is the product of moment of inertia and angular velocity.

Angular Momentum of a Point Particle

Angular momentum for a point particle relative to an origin.

L⃗=r⃗×p⃗\vec{L} = \vec{r} \times \vec{p}

Variables

SymbolDescriptionUnit
L⃗\vec{L}Angular momentum vectorkg⋅m2/skg\cdot m^2/s
r⃗\vec{r}Position vectorm
p⃗\vec{p}Linear momentum vectorkg⋅m/skg\cdot m/s

Angular Momentum of a Rigid Body

Angular momentum for a rigid body rotating around a fixed axis.

L⃗=Iω⃗\vec{L} = I\vec{\omega}

Variables

SymbolDescriptionUnit
L⃗\vec{L}Angular momentum vectorkg⋅m2/skg\cdot m^2/s
IIMoment of inertiakg⋅m2kg\cdot m^2
ω⃗\vec{\omega}Angular velocity vectorrad/s

Conservation of Angular Momentum

Just as ΣF=dp/dt\Sigma F = dp/dt, the net torque equals the rate of change of angular momentum: Στ⃗=dL⃗/dt\Sigma \vec{\tau} = d\vec{L}/dt.

Conservation Principle

Conservation of Angular Momentum: If the net external torque on a system is zero (Στ⃗ext=0\Sigma \vec{\tau}_{ext} = 0), the total angular momentum of the system is conserved (L⃗i=L⃗f\vec{L}_i = \vec{L}_f). This explains why a figure skater spins faster when they pull their arms in (decreasing II must increase ω\omega to keep L=IωL=I\omega constant).

Interactive Simulation

Use this angular momentum model to see why pulling mass inward makes angular speed rise when external torque is negligible.

Angular Momentum Skater Simulator

Concept and model scope

Move two 1.5 kg point masses inward or outward. With negligible external torque, angular momentum is conserved: decreasing the arm radius lowers moment of inertia and raises angular speed, while increasing it does the opposite.

Model scope: Use the displayed units and idealizations, then verify the governing balance or compatibility equation before interpreting the result.

Initial Arm Radius (ri)

Initial Arm Radius (ri)

Initial Arm Radius (ri) is an adjustable engineering parameter. The displayed result and geometry should update directly from this value.

Range: 0.40–2.00 m. Step: 0.05 m.

1.30 m
Current Arm Radius (rc)

Current Arm Radius (rc)

Current Arm Radius (rc) is an adjustable engineering parameter. The displayed result and geometry should update directly from this value.

Range: 0.30–2.00 m. Step: 0.05 m.

0.70 m
Core Skater Inertia (I_body)

Core Skater Inertia (I_body)

Core Skater Inertia (I_body) is an adjustable engineering parameter. The displayed result and geometry should update directly from this value.

Range: 0.5–6.0 kg·m². Step: 0.1 kg·m².

2.0 kg·m²
Initial Angular Speed (ωi)

Initial Angular Speed (ωi)

Initial Angular Speed (ωi) is an adjustable engineering parameter. The displayed result and geometry should update directly from this value.

Range: 0.5–6.0 rad/s. Step: 0.1 rad/s.

2.5 rad/s
Governing Laws
Moment of Inertia
I=Ibody+2m⋅r2I = I_{body} + 2m \cdot r^2
Conservation of Angular Momentum
L=Ii⋅ωi=If⋅ωfL = I_i \cdot \omega_i = I_f \cdot \omega_f
Rotating skater demonstrating the conservation of angular momentumdashed: rᵢ · solid: r_cring radius represents geometry, not angular speed
Angular Momentum (L)
17.68 kg·m²/s
Current Angular Speed (ω)
5.09 rad/s
Initial Inertia (Iᵢ)
7.07 kg·m²
Current Inertia (I_c)
3.47 kg·m²

Parallel-Axis Theorem in Practice

Calculating Complex Inertia

The Parallel-Axis Theorem is not just an abstract concept; it is vital for calculating the moment of inertia of complex, composite engineering shapes (like I-beams or rotating eccentric cams) where the axis of rotation does not pass through the center of mass of every individual component.

By breaking a complex shape into simple geometric parts (rectangles, circles), finding their individual moments of inertia about their own centers of mass, and then using the Parallel-Axis Theorem (I=Icm+Md2I = I_{cm} + Md^2) to shift those moments to the global axis of rotation, engineers can analyze the rotational dynamics of virtually any rigid body.

Key Takeaways
  • Rotational kinematics equations (θ,ω,α\theta, \omega, \alpha) are exactly analogous to linear equations (x,v,ax, v, a).
  • Torque (τ⃗=r⃗×F⃗\vec{\tau} = \vec{r} \times \vec{F}) is the rotational analog to force, causing angular acceleration.
  • Moment of Inertia (I=∑mr2I = \sum mr^2) is the rotational analog to mass, representing resistance to angular acceleration. It depends on mass distribution.
  • Newton's Second Law for rotation is Στ⃗=Iα⃗\Sigma \vec{\tau} = I \vec{\alpha}.
  • A spinning object possesses Rotational Kinetic Energy (KR=12Iω2K_R = \frac{1}{2}I\omega^2).
  • Angular Momentum (L⃗=Iω⃗\vec{L} = I\vec{\omega}) is conserved if the net external torque is zero.