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Cables2D

Cable with one concentrated load

Select polygonal, parabolic, or catenary cable models and reject compression, slack, and invalid support conditions.

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Interactive engineering simulation

Cable with One Concentrated Load

Use a prescribed sag at the load point to solve two straight cable segments and their tensions.

Tension only
Model distinction: point loads create straight polygonal segments; load uniform per horizontal metre creates a parabola; self-weight uniform per cable metre creates a catenary. These models are never silently substituted for one another.
The prescribed sag is measured below the support chord at the first load location, x=10.00 m.
x=0.00 m; sag below chord=0.00 mx=10.00 m; sag below chord=5.00 mx=24.00 m; sag below chord=0.00 m18.0 kNT=23.5 kNT=22.3 kNPolygonal cable · discrete point loadsSpan 24.0 m · right support 0.0 m above left
Horizontal component H
21.00 kN
Maximum tension
23.48 kN
Left vertical component
10.50 kN
Right vertical component
7.50 kN
Horizontal span
24 m
m
1060

Drag for exploration or enter an exact value. Press Enter to apply; Escape restores the current value.

Sag below support chord
5.00 m
m
1.0014.00

Drag for exploration or enter an exact value. Press Enter to apply; Escape restores the current value.

Right support elevation above left
0.0 m
m
-8.08.0

Drag for exploration or enter an exact value. Press Enter to apply; Escape restores the current value.

Point load P1
18 kN
kN
150

Drag for exploration or enter an exact value. Press Enter to apply; Escape restores the current value.

Point load P1 position
10.0 m
m
0.523.5

Drag for exploration or enter an exact value. Press Enter to apply; Escape restores the current value.

HH remains constant through every segment, while Ti=H2+Vi2T_i=\sqrt{H^2+V_i^2} changes with segment slope. A negative free-support reaction is reported as a hold-down requirement rather than accepted silently.
Model scope and verification

Use the displayed units and idealizations, then verify the governing balance or compatibility equation before interpreting the result.