Kinetics of Rigid Bodies: Impulse and Momentum - Theory & Concepts - Bullet Rod

Analysis of impulsive forces and moments acting on rigid bodies, introducing angular momentum and the principle of impulse and momentum.

Angular Momentum: Bullet Striking a Rod

Bullet Mass (

m

)0.010 kg

Bullet Speed (

v_0

)400 m/s

Rod Mass (

M

)4 kg

Rod Length (

L

)1.0 m

Impact Point (

d/L

)50% from pivot

Conservation of

H_O

m v_0 d = I_{\text{total}}\,\omega

I_{\text{total}} = \tfrac{1}{3}ML^2 + md^2

= 1.333 + 0.0025 = 1.3358\,\text{kg·m}^2

H_0 = 2.0000\,\text{kg·m}^2/\text{s}

\omega = 1.50\,\text{rad/s}

KE before:800.0 J

KE after:1.5 J

Energy lost:798.5 J (99.8%)

Bullet (m = 0.010 kg)

Rod (M = 4 kg)

Impact point d = 0.50 m

Related simulations