Kinetics of Rigid Bodies: Impulse and Momentum

Learning Objectives

  • Define linear and angular impulse and momentum for a rigid body.
  • Apply the principle of impulse and momentum to solve kinetics problems involving force, mass, velocity, and time.
  • Analyze systems of interacting rigid bodies.
  • Apply conservation of linear and angular momentum to collision and impact problems.
  • Understand the mechanics of eccentric impact.

This method relates forces and moments acting over a time interval to the change in both linear and angular momentum of the body. It is particularly powerful for impact problems and situations involving variable forces, providing a direct relation between time and velocity.

Civil Engineering Applications

Impulse and momentum methods are frequently applied when examining impulsive impact forces in civil structures:

  • Vehicular Collision: Analyzing impact forces of cars or ships colliding with bridge piers over short time durations.
  • Pile Driving: Studying the rapid transfer of momentum from the falling pile hammer to the driven pile.
  • Dynamic Impact: Evaluating the response of slabs when struck by dropped objects in industrial facilities.

Impulse

The integral of a force or couple moment over the time interval during which it acts. It represents the total "push" or "twist" given to a body.

Momentum

The product of a body's mass or mass moment of inertia and its corresponding velocity. Linear momentum is mvm\mathbf{v}, and angular momentum is Iฯ‰I\mathbf{\omega}.

Principle of Impulse and Momentum

The principle states that the initial momentum of the system plus the sum of all external impulses acting on the system equals the final momentum of the system.

Linear Impulse-Momentum Equation

The change in linear momentum of the center of mass G is equal to the linear impulse of external forces.

m(vG)1+โˆ‘โˆซt1t2Fโ€‰dt=m(vG)2m(v_G)_1 + \sum \int_{t_1}^{t_2} \mathbf{F} \, dt = m(v_G)_2

Variables

SymbolDescriptionUnit
mmMass of the rigid bodykg
(vG)1,(vG)2(v_G)_1, (v_G)_2Initial and final velocities of the center of massm/s
F\mathbf{F}External forces acting on the bodyN
t1,t2t_1, t_2Initial and final timess

Angular Impulse-Momentum Equation

The change in angular momentum about the center of mass G is equal to the angular impulse of external moments about G.

IGฯ‰1+โˆ‘โˆซt1t2MGโ€‰dt=IGฯ‰2I_G \omega_1 + \sum \int_{t_1}^{t_2} M_G \, dt = I_G \omega_2

Variables

SymbolDescriptionUnit
IGI_GMass moment of inertia about the center of masskgยทmยฒ
ฯ‰1,ฯ‰2\omega_1, \omega_2Initial and final angular velocitiesrad/s
MGM_GExternal moments about the center of massNยทm
t1,t2t_1, t_2Initial and final timess

Angular Momentum (HH)

Angular momentum represents the quantity of rotation of a body, which is the product of its moment of inertia and its angular velocity.

Angular Momentum About Center of Mass

Calculates angular momentum about the center of mass G.

HG=IGฯ‰H_G = I_G \omega

Variables

SymbolDescriptionUnit
HGH_GAngular momentum about Gkgยทmยฒ/s
IGI_GMass moment of inertia about Gkgยทmยฒ
ฯ‰\omegaAngular velocityrad/s

Angular Momentum About a Fixed Point

Calculates angular momentum about a fixed point O.

HO=IOฯ‰H_O = I_O \omega

Variables

SymbolDescriptionUnit
HOH_OAngular momentum about fixed point Okgยทmยฒ/s
IOI_OMass moment of inertia about fixed point Okgยทmยฒ
ฯ‰\omegaAngular velocityrad/s

System of Rigid Bodies

When multiple rigid bodies interact, the principles of linear and angular impulse-momentum can be applied to the entire system.

System of Interacting Bodies

For a system of interacting rigid bodies, the internal forces between them generate equal and opposite impulses that sum to zero. Therefore, only external forces create a net impulse on the system.

Linear Impulse-Momentum for a System

The total linear momentum of the system is the sum of the linear momenta of each individual body.

(Lsys)1+โˆ‘โˆซt1t2Fextdt=(Lsys)2(\mathbf{L}_{sys})_1 + \sum \int_{t_1}^{t_2} \mathbf{F}_{ext} dt = (\mathbf{L}_{sys})_2

Variables

SymbolDescriptionUnit
(Lsys)1,(Lsys)2(\mathbf{L}_{sys})_1, (\mathbf{L}_{sys})_2Initial and final total linear momenta of the systemkgยทm/s
Fext\mathbf{F}_{ext}External forces acting on the systemN
t1,t2t_1, t_2Initial and final timess

Angular Impulse-Momentum for a System

The total angular momentum of the system about a fixed point O is the sum of the angular momenta of each body about O.

(Hsys)1+โˆ‘โˆซt1t2(MO)extdt=(Hsys)2(\mathbf{H}_{sys})_1 + \sum \int_{t_1}^{t_2} (M_O)_{ext} dt = (\mathbf{H}_{sys})_2

Variables

SymbolDescriptionUnit
(Hsys)1,(Hsys)2(\mathbf{H}_{sys})_1, (\mathbf{H}_{sys})_2Initial and final total angular momenta about Okgยทmยฒ/s
(MO)ext(M_O)_{ext}External moments about O acting on the systemNยทm
t1,t2t_1, t_2Initial and final timess

Conservation of Momentum

The conservation laws are powerful when analyzing the interaction of bodies where external impulses are negligible, such as during collisions or explosions in free space.

Conservation of Linear Momentum

If there is no net external linear impulse acting on the system (โˆ‘โˆซFโ€‰dt=0\sum \int \mathbf{F} \, dt = 0), then the total linear momentum is conserved.

Conservation of Linear Momentum Equation

Expresses that the initial total linear momentum equals the final total linear momentum.

L1=L2\mathbf{L}_1 = \mathbf{L}_2

Variables

SymbolDescriptionUnit
L1\mathbf{L}_1Total initial linear momentumkgยทm/s
L2\mathbf{L}_2Total final linear momentumkgยทm/s

Conservation of Angular Momentum

If there is no net external angular impulse acting about a point P (โˆ‘โˆซMPโ€‰dt=0\sum \int M_P \, dt = 0), then the total angular momentum about that point is conserved. This often occurs when all external forces pass through a common point P or are zero.

Conservation of Angular Momentum Equation

Expresses that the initial total angular momentum about P equals the final total angular momentum about P.

(HP)1=(HP)2(\mathbf{H}_P)_1 = (\mathbf{H}_P)_2

Variables

SymbolDescriptionUnit
(HP)1(\mathbf{H}_P)_1Total initial angular momentum about point Pkgยทmยฒ/s
(HP)2(\mathbf{H}_P)_2Total final angular momentum about point Pkgยทmยฒ/s

Eccentric Impact

Eccentric Impact

An eccentric impact occurs when the line of action of the impulsive forces acting on a rigid body does not pass through its center of mass, resulting in both translation and rotation.

When a rigid body is subjected to an eccentric impact, it undergoes a change in both translational and rotational velocity.

Eccentric Impact Principles

  • The point of impact experiences a large impulsive force โˆซFdt\int \mathbf{F} dt.
  • This impulsive force changes the linear momentum: m(vG)1+โˆซFdt=m(vG)2m(\mathbf{v}_G)_1 + \int \mathbf{F} dt = m(\mathbf{v}_G)_2.
  • Because the line of impact does not pass through the center of mass GG, the force creates an angular impulse, changing the angular momentum: IGฯ‰1+โˆซrร—Fdt=IGฯ‰2I_G \omega_1 + \int \mathbf{r} \times \mathbf{F} dt = I_G \omega_2.
  • If the object is constrained by a pin, analyzing angular momentum about the fixed pivot eliminates the need to solve for the unknown pin reaction impulses.

Interactive Simulation

Interact with the simulation below to explore eccentric impact on a rod.

Angular Momentum: Bullet Striking a Rod

System Parameters

Angular Momentum Solver

Conservation of HOH_O:
mv0d=Itotalโ€‰ฯ‰m v_0 d = I_{\text{total}}\,\omega
Itotal=13ML2+md2I_{\text{total}} = \tfrac{1}{3}ML^2 + md^2
=1.333+0.0025=1.3358โ€‰kgโ‹…m2= 1.333 + 0.0025 = 1.3358\,\text{kgยทm}^2
H0=2.0000โ€‰kgโ‹…m2/sH_0 = 2.0000\,\text{kgยทm}^2/\text{s}
ฯ‰=1.50โ€‰rad/s\omega = 1.50\,\text{rad/s}
KE before:800.0 J
KE after:1.5 J
Energy lost:798.5 J (99.8%)
Bulletโ€“Rod Angular Momentum WorkspaceO (Pivot)Ld = 0.50mReady โ€” click Fire!
Bullet (m = 0.010 kg)
Rod (M = 4 kg)
Impact point d = 0.50 m
Key Takeaways
  • Impulse-Momentum Principle (L1+ฮฃI=L2L_1 + \Sigma I = L_2) applies to both linear (mvmv) and angular (Iฯ‰I\omega) momentum.
  • System of Rigid Bodies: Internal impulses cancel; only external forces and moments change the total linear and angular momentum.
  • Angular Momentum (H=Iฯ‰H = I\omega) is conserved when the net external moment is zero.
  • Impact Problems often use conservation of angular momentum about a fixed pivot to eliminate unknown reaction impulses.
  • Eccentric Impact imparts both a linear velocity change and a rotational velocity change due to the moment arm of the impulse.