Fluid Mechanics

Learning Objectives

  • Define density and pressure in the context of fluid statics.
  • Calculate hydrostatic pressure and apply Pascal's Principle.
  • Understand and apply Archimedes' Principle to buoyancy problems.
  • State the assumptions of ideal fluid flow.
  • Apply the Equation of Continuity and Bernoulli's Equation to fluid dynamics.

Fluid mechanics is the study of fluids (liquids and gases) both at rest (statics) and in motion (dynamics). It is a foundational subject for civil engineering branches like hydraulics, water resources, and environmental engineering.

Fluid Statics

Fluid Statics Concepts

Fluids differ from solids because they cannot sustain shear stress while at rest. They flow and take the shape of their container.

Density (ρ\rho)

Mass per unit volume. It is a fundamental property. The SI unit is kg/m3\text{kg/m}^3.

Density Equation

Calculates density from mass and volume.

ρ=mV\rho = \frac{m}{V}

Variables

SymbolDescriptionUnit
ρ\rhoDensitykg/m3kg/m^3
mmMasskg
VVVolumem3m^3

Water Density

For water at 4C4^\circ\text{C}, ρ1000 kg/m3\rho \approx 1000 \text{ kg/m}^3.

Specific Gravity (SG)

The ratio of the density of a substance to the density of a reference substance (usually water). It is a dimensionless number.

Specific Gravity Equation

Ratio of substance density to reference density.

SG=ρsubstanceρwaterSG = \frac{\rho_{\text{substance}}}{\rho_{\text{water}}}

Variables

SymbolDescriptionUnit
SGSGSpecific Gravitydimensionless
ρsubstance\rho_{\text{substance}}Density of the substancekg/m3kg/m^3
ρwater\rho_{\text{water}}Density of waterkg/m3kg/m^3

Pressure (PP)

Pressure (PP) Concepts

Instead of dealing with forces on specific particles (which are constantly moving in a fluid), we deal with pressure.

Pressure (PP)

The magnitude of the normal force exerted by a fluid per unit area of a surface. It is a scalar quantity.

Pressure Equation

Calculates pressure from force and area.

P=FAP = \frac{F}{A}

Variables

SymbolDescriptionUnit
PPPressurePa
FFNormal forceN
AAAream2m^2

Pressure vs. Force

Pressure vs. Force: Pressure acts perpendicular to any surface it contacts. While force is a vector, pressure itself has no direction.

Hydrostatic Pressure

Hydrostatic Pressure Concepts

The pressure at any depth in a stationary liquid depends only on the depth, the density of the liquid, and gravity.

Hydrostatic Equation

Calculates absolute pressure at a given depth.

P=P0+ρghP = P_0 + \rho g h

Variables

SymbolDescriptionUnit
PPAbsolute pressure at depth hPa
P0P_0Pressure at the surface (often atmospheric)Pa
ρ\rhoDensity of the fluidkg/m3kg/m^3
ggAcceleration due to gravitym/s2m/s^2
hhDepth below the surfacem

Pressure and Depth Relationship

This equation shows that pressure increases linearly with depth in an incompressible fluid (like water).

Interactive Simulation

Use this hydrostatic model to see how depth, density, and area control pressure and resultant force.

Interactive Physics Simulation

Hydrostatic Pressure Field & Gate Simulator

Submerge a rectangular vertical gate in a fluid field. Watch the hydrostatic pressure prism grow linearly with depth, and observe how the resultant force anchors precisely at the Center of Pressure (y_cp).

Fresh Water
Fluid Preset
5.0 m
1000 kg/m³
2.0 m
1.5 m
Governing Formulas
Resultant Hydrostatic Force
FR=PcA=(ρghc)(bh)F_R = P_c \cdot A = (\rho g h_c) \cdot (b \cdot h)
Vertical Center of Pressure
ycp=hc+e=hc+h212hcy_{cp} = h_c + e = h_c + \frac{h^2}{12 h_c}
Submerged gate hydrostatic load profile showing center of pressure offsetFree SurfaceFrpressure increases linearly with depth (Pc = ρgh)
Pressure at Centroid (Pc)
49.05 kPa
Resultant Force (Fr)
147.15 kN
Centroid Depth (hc)
5.00 m
Center of Pressure (y_cp)
5.07 m

Pascal's Principle

Pascal's Principle Concepts

If you apply pressure to an enclosed, incompressible fluid, that change in pressure is transmitted undiminished to every part of the fluid and the walls of its container.

Pascal's Principle

Pressure change in an enclosed fluid.

ΔP=constant everywhere\Delta P = \text{constant everywhere}

Variables

SymbolDescriptionUnit
ΔP\Delta PChange in pressurePa

Hydraulic Lifts

This is the principle behind hydraulic lifts. A small force F1F_1 applied over a small area A1A_1 creates a pressure ΔP=F1/A1\Delta P = F_1/A_1. This exact same pressure appears on a larger area A2A_2, producing a much larger force F2F_2.

Hydraulic Lift Force Equation

Calculates the output force of a hydraulic lift given the input force and area ratio.

F2=F1(A2A1)F_2 = F_1 \left( \frac{A_2}{A_1} \right)

Variables

SymbolDescriptionUnit
F2F_2Output force on the larger pistonN
F1F_1Input force on the smaller pistonN
A2A_2Area of the larger pistonm2m^2
A1A_1Area of the smaller pistonm2m^2

Archimedes' Principle (Buoyancy)

Archimedes' Principle (Buoyancy) Concepts

Any object, wholly or partially immersed in a fluid, is buoyed up by a force equal to the weight of the fluid displaced by the object.

Buoyant Force (FBF_B)

Calculates the upward buoyant force on an object in a fluid.

FB=ρfluidVsubmergedgF_B = \rho_{\text{fluid}} V_{\text{submerged}} g

Variables

SymbolDescriptionUnit
FBF_BBuoyant forceN
ρfluid\rho_{\text{fluid}}Density of the fluidkg/m3kg/m^3
VsubmergedV_{\text{submerged}}Submerged volume of the objectm3m^3
ggAcceleration due to gravitym/s2m/s^2

Density and Flotation

Notice that the buoyant force depends on the density of the fluid, not the object, and the volume of the object that is actually submerged (VsubmergedV_{\text{submerged}}).

  • If an object is denser than the fluid (ρobj>ρfluid\rho_{obj} > \rho_{fluid}), it will sink (its weight WobjW_{obj} is greater than the maximum FBF_B).
  • If it is less dense (ρobj<ρfluid\rho_{obj} < \rho_{fluid}), it will float. In equilibrium floating, it displaces a volume of fluid whose weight exactly equals its own total weight (FB=WobjF_B = W_{obj}).

Interactive Simulation

Use this buoyancy model to compare object weight with displaced fluid weight.

Interactive Physics Simulation

Archimedes' Principle & Buoyancy

Adjust the density of the block and the fluid. Archimedes' principle states that the buoyant force equals the weight of the fluid displaced by the object.

Floats
600 kg/m³
Styrofoam (100)Wood (600)Brick (2000)
1000 kg/m³
Oil (800)Water (1000)Honey (1400)
1.0
Governing Formulas
Weight of BlockW=mg=ρobjVgW = m \cdot g = \rho_{obj} \cdot V \cdot g
Buoyant ForceFb=ρfluidVsubgF_b = \rho_{fluid} \cdot V_{sub} \cdot g
Weight of Block
5,886 N
Buoyant Force
5,886 N
Fraction Submerged
60.0%

Fluid Dynamics

Fluid Dynamics Concepts

When fluids move, things get complicated quickly. In introductory physics and engineering, we usually start with an idealized model of fluid flow: ideal fluid flow.

Assumptions of Ideal Fluid Flow

  • Steady Flow: The velocity of the fluid at any given point is constant over time.
  • Incompressible: The density of the fluid is constant (a very good assumption for liquids).
  • Nonviscous (Inviscid): Internal friction within the fluid is zero.
  • Irrotational: Fluid particles do not rotate about their own centers of mass.

The Equation of Continuity

The Equation of Continuity Concepts

For an incompressible fluid flowing steadily through a pipe of varying cross-sectional area, the volume flow rate (QQ) must remain constant everywhere. What goes in must come out.

Volume Flow Rate (QQ)

The volume of fluid passing a given cross-section per unit time. The SI unit is m3/s\text{m}^3/\text{s}.

Volume Flow Rate Equation

Calculates volume flow rate from area and fluid speed.

Q=ΔVΔt=AvQ = \frac{\Delta V}{\Delta t} = A v

Variables

SymbolDescriptionUnit
QQVolume flow ratem3/sm^3/s
ΔV\Delta VChange in volumem3m^3
Δt\Delta tTime intervals
AACross-sectional aream2m^2
vvFluid speedm/s

Equation of Continuity

Relates area and velocity at two points in steady flow.

A1v1=A2v2A_1 v_1 = A_2 v_2

Variables

SymbolDescriptionUnit
A1A_1Cross-sectional area at point 1m2m^2
v1v_1Fluid speed at point 1m/s
A2A_2Cross-sectional area at point 2m2m^2
v2v_2Fluid speed at point 2m/s

Flow Speed Example

This explains why a river speeds up when it passes through a narrow gorge (A2<A1    v2>v1A_2 < A_1 \implies v_2 > v_1).

Bernoulli's Equation

Bernoulli's Equation Concepts

Bernoulli's equation is essentially a statement of the conservation of mechanical energy applied to ideal fluid flow. It relates pressure, flow speed, and elevation along a streamline.

The work done on a fluid element as it moves through a pipe changes its kinetic and potential energy.

Bernoulli's Equation

Conservation of energy principle applied to ideal fluid flow.

P1+12ρv12+ρgy1=P2+12ρv22+ρgy2P_1 + \frac{1}{2}\rho v_1^2 + \rho g y_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho g y_2

Variables

SymbolDescriptionUnit
P1P_1Absolute pressure at point 1Pa
v1v_1Fluid speed at point 1m/s
y1y_1Elevation at point 1m
P2P_2Absolute pressure at point 2Pa
v2v_2Fluid speed at point 2m/s
y2y_2Elevation at point 2m
ρ\rhoFluid densitykg/m3kg/m^3
ggAcceleration due to gravitym/s2m/s^2
12ρv2\frac{1}{2}\rho v^2Dynamic pressure (kinetic energy per unit volume)Pa
ρgy\rho g yStatic pressure due to elevation (potential energy per volume)Pa

The Bernoulli Effect

The Bernoulli Effect: If a fluid flows horizontally (y1=y2y_1 = y_2), the equation simplifies to P1+12ρv12=P2+12ρv22P_1 + \frac{1}{2}\rho v_1^2 = P_2 + \frac{1}{2}\rho v_2^2. This shows that where the speed of the fluid is high, the pressure is low, and vice-versa. This principle is key to understanding airplane lift, carburetors, and the Venturi tube.

Interactive Simulation

Use this pipe-flow model to connect continuity with the Bernoulli pressure-head tradeoff.

Interactive Physics Simulation

Continuity & Bernoulli Venturi Simulator

Adjust the upstream and throat cross-sectional areas. Observe how fluid streamlines compress and accelerate inside the narrow constriction, inducing a corresponding pressure drop.

0.12
0.05
0.24 m³/s
0.4 m
Governing Formulas
Continuity Equation
Q=A1v1=A2v2Q = A_1 \cdot v_1 = A_2 \cdot v_2
Bernoulli's Energy Balance
Δh=v22v122g+hL\Delta h = \frac{v_2^2 - v_1^2}{2g} + h_L
Venturi tube flow field simulator with acceleration and pressure head pipesP₁ headP₂ head
Upstream Velocity (v1)
2.00 m/s
Constriction Velocity (v2)
4.80 m/s
Total Head Drop (Δh)
1.37 m

Torricelli's Theorem

Torricelli's Theorem Concepts

A direct application of Bernoulli's equation is finding the speed of fluid exiting a small hole at the bottom of an open tank. If the hole is a distance hh below the surface, the surface area is much larger than the hole (vsurface0v_{surface} \approx 0), and both are at atmospheric pressure, Bernoulli's equation simplifies to Torricelli's Theorem.

Torricelli's Theorem

Fluid exit speed from an open tank.

vexit=2ghv_{exit} = \sqrt{2gh}

Variables

SymbolDescriptionUnit
vexitv_{exit}Exit velocity of fluidm/s
ggAcceleration due to gravitym/s2m/s^2
hhDepth of hole below fluid surfacem

Free Fall Analogy

This shows the fluid exits with the same speed an object would have if dropped in free fall from a height hh.

Variation of Pressure with Depth

The Hydrostatic Paradox

The equation P=P0+ρghP = P_0 + \rho gh implies that the pressure at a given depth in a static fluid is independent of the shape of the container or the total volume of fluid present. This leads to the "Hydrostatic Paradox":

If you have three containers of wildly different shapes (one wide, one narrow, one conical) but all filled to the exact same height hh with the same fluid, the pressure at the bottom of all three containers is identical. Consequently, if the bottom area AA is the same, the total force on the bottom of each container is exactly the same, regardless of how much total fluid is inside!

Key Takeaways
  • Fluid Statics is governed by pressure increasing with depth (P=P0+ρghP = P_0 + \rho gh) and Pascal's Principle (pressure applied is transmitted undiminished).
  • Archimedes' Principle states that buoyancy is an upward force equal to the weight of displaced fluid (FB=ρfVsubgF_B = \rho_f V_{sub} g).
  • Fluid Dynamics for ideal fluids relies on conservation principles.
  • The Equation of Continuity (A1v1=A2v2A_1v_1 = A_2v_2) is the conservation of mass/volume flow.
  • Bernoulli's Equation (P+12ρv2+ρgy=constP + \frac{1}{2}\rho v^2 + \rho gy = \text{const}) is the conservation of energy, showing that pressure drops when speed increases horizontally.