Back to Algebra repository
Algebra2D

Word Problems - Theory & Concepts

Techniques and strategies for solving common algebraic word problems including age, mixture, work, motion, and clock problems.

Open the complete lesson

Distance-Rate-Time Procedure Visualizer

Problem Parameters

40 mph
60 mph
2 hrs
A
Dist A: 80.0 mi
B
Dist B: 0.0 mi
Time (t): 0.00 hr

Solution Procedure

1. Define Variables

Let tt = time since Train B started (hrs).

Train A's time = t+2t + 2 hrs.

Train A's rate = 4040 mph.

Train B's rate = 6060 mph.

2. Build Equations (d = r × t)

Distance A:

dA=40(t+2)d_A = 40(t + 2)

Distance B:

dB=60td_B = 60t
3. Solve for Intercept (d_A = d_B)
60t=40(t+2)60t = 40(t + 2)60t=40t+8060t = 40t + 8020t=8020t = 80t=8020t = \frac{80}{20}
4. Final Result & Unit Check

Time to catch up: 4.00 hours

Verify distance:

d_B = 60 × 4.00 = 240.00 mi

d_A = 40 × (4.00 + 2) = 240.00 mi