Kinematics

Learning Objectives

  • Define and calculate displacement, velocity, and acceleration with civil engineering context.
  • Understand the difference between average and instantaneous kinematic quantities.
  • Derive and apply the kinematic equations for 1D motion with constant acceleration.
  • Analyze 2D projectile motion by separating it into independent horizontal and vertical components.
  • Calculate tangential and centripetal acceleration in circular motion for transportation design.
  • Solve relative motion problems in 1D and 2D using vector addition.
Kinematics is the branch of classical mechanics that describes the motion of points, bodies (objects), and systems of bodies without considering the forces that cause them to move. It is essentially the "geometry of motion." Before we can understand why objects move (Dynamics), we must first master how to describe that motion. Kinematics provides the vocabulary and equations necessary to track an object's position, speed, and acceleration over time. This is essential for traffic engineering, robotics, and aerospace trajectories.

Key Kinematic Quantities

Key Kinematic Quantities Concepts

To describe motion, we use a specific set of parameters. All of these (except time and distance) are vector quantities.

Displacement (Δx\Delta x)

The change in position of an object. It is a vector pointing from the initial position to the final position.

Δx=xfxi\Delta \vec{x} = \vec{x}_f - \vec{x}_i

Note: Displacement is not the same as the total distance traveled, which is a scalar representing the actual path length.

Average vs Instantaneous

Average vs Instantaneous Concepts

In kinematics, it is critical to distinguish between average values over a time interval and instantaneous values at a specific moment.

Average Velocity (vavg\vec{v}_{avg})

The total displacement divided by the time interval during which the displacement occurred. It points in the same direction as the displacement.

vavg=ΔxΔt\vec{v}_{avg} = \frac{\Delta \vec{x}}{\Delta t}

Contrast this with average speed, which is total distance divided by total time (a scalar).

Instantaneous Velocity (v(t)\vec{v}(t))

The velocity of an object at a specific instant in time. Mathematically, it is the limit of the average velocity as the time interval approaches zero. It is the derivative of position with respect to time.

v(t)=limΔt0ΔxΔt=dxdt\vec{v}(t) = \lim_{\Delta t \to 0} \frac{\Delta \vec{x}}{\Delta t} = \frac{d\vec{x}}{dt}

Acceleration (a\vec{a})

The rate of change of velocity with respect to time. An object is accelerating if its speed changes, its direction changes, or both.

aavg=ΔvΔt\vec{a}_{avg} = \frac{\Delta \vec{v}}{\Delta t}a(t)=limΔt0ΔvΔt=dvdt=d2xdt2\vec{a}(t) = \lim_{\Delta t \to 0} \frac{\Delta \vec{v}}{\Delta t} = \frac{d\vec{v}}{dt} = \frac{d^2\vec{x}}{dt^2}

Graphical Analysis of Motion

Position-Time Graph (x vs t)

A graph where the slope of the tangent line at any point represents the instantaneous velocity. A constant slope indicates constant velocity. A curve indicates changing velocity (acceleration).

Velocity-Time Graph (v vs t)

A graph where the slope of the tangent line represents instantaneous acceleration. The area under the curve between two times represents the displacement.

Acceleration-Time Graph (a vs t)

A graph where the area under the curve represents the change in velocity.

Graphical Analysis of Motion Concepts

Graphs are powerful tools for visualizing kinematics. The slope and area under curves provide vital information regarding position, velocity, and acceleration over time.

Deriving the Kinematic Equations (Calculus Approach)

Deriving the Kinematic Equations (Calculus Approach) Concepts

For engineering mechanics, it is essential to understand that kinematic equations are derived using fundamental calculus operations on the definitions of velocity and acceleration.

Given a=dv/dta = dv/dt, we can integrate with respect to time to find velocity. If acceleration aa is constant:

Velocity from Constant Acceleration

Integrates constant acceleration over time to find the velocity equation.

v0vdv=0tadt    v=v0+at\int_{v_0}^{v} dv = \int_{0}^{t} a \, dt \implies v = v_0 + at

Variables

SymbolDescriptionUnit
vvFinal velocitym/s
v0v_0Initial velocitym/s
aaConstant accelerationm/s2m/s^2
ttTime intervals

Deriving Position from Velocity

Given v=dx/dtv = dx/dt, we substitute the velocity equation and integrate again to find position:

Position from Constant Acceleration

Integrates velocity over time to find the position equation under constant acceleration.

x0xdx=0t(v0+at)dt    x=x0+v0t+12at2\int_{x_0}^{x} dx = \int_{0}^{t} (v_0 + at) \, dt \implies x = x_0 + v_0 t + \frac{1}{2}at^2

Variables

SymbolDescriptionUnit
xxFinal positionm
x0x_0Initial positionm
v0v_0Initial velocitym/s
aaConstant accelerationm/s2m/s^2
ttTime intervals

Time-Independent Derivation

If we need a relationship independent of time, we use the chain rule: a=dvdt=dvdxdxdt=vdvdxa = \frac{dv}{dt} = \frac{dv}{dx} \frac{dx}{dt} = v \frac{dv}{dx}. Separating variables and integrating yields v2=v02+2a(xx0)v^2 = v_0^2 + 2a(x - x_0).

1D Motion with Constant Acceleration

1D Motion with Constant Acceleration Concepts

When an object's acceleration is constant (like a car braking uniformly, or an object in free fall near Earth's surface), its motion can be completely described by four foundational equations, often called the "Big Four" kinematic equations. As shown above, these are derived directly from calculus.

Kinematic Equation 1: Velocity as a Function of Time

Calculates final velocity given initial velocity, constant acceleration, and time.

vf=vi+atv_f = v_i + at

Variables

SymbolDescriptionUnit
vfv_fFinal velocitym/s
viv_iInitial velocitym/s
aaConstant accelerationm/s2m/s^2
ttTime intervals

Kinematic Equation 2: Displacement as a Function of Time

Calculates displacement given initial velocity, time, and constant acceleration.

Δx=vit+12at2\Delta x = v_i t + \frac{1}{2}at^2

Variables

SymbolDescriptionUnit
Δx\Delta xDisplacementm
viv_iInitial velocitym/s
aaConstant accelerationm/s2m/s^2
ttTime intervals

Kinematic Equation 3: Velocity as a Function of Displacement

Calculates final velocity without knowing the time interval.

vf2=vi2+2aΔxv_f^2 = v_i^2 + 2a\Delta x

Variables

SymbolDescriptionUnit
vfv_fFinal velocitym/s
viv_iInitial velocitym/s
aaConstant accelerationm/s2m/s^2
Δx\Delta xDisplacementm

Kinematic Equation 4: Displacement using Average Velocity

Calculates displacement using initial and final velocity without knowing acceleration.

Δx=(vi+vf2)t\Delta x = \left(\frac{v_i + v_f}{2}\right)t

Variables

SymbolDescriptionUnit
Δx\Delta xDisplacementm
viv_iInitial velocitym/s
vfv_fFinal velocitym/s
ttTime intervals

Interactive Simulation

Use the graph simulator to see how changing initial velocity, acceleration, and time reshapes the position-time and velocity-time curves.

Interactive Physics Simulation

Kinematics Motion & Graph Simulator

Adjust initial velocity and acceleration, and scrub time. Analyze how position, velocity, and acceleration curves behave, and observe that the area under the v-t curve equals displacement.

Select Active Graph
6.0 m/s
1.5 m/s²
8.0 s
4.0 s
Governing Formulas
Position & Velocityx(t)=v0t+12at2,v(t)=v0+atx(t) = v_0 t + \frac{1}{2}a t^2, \quad v(t) = v_0 + a t
Calculus Theoremv(t)=dxdt,x(t)=0tv(τ)dτ(Area)v(t) = \frac{dx}{dt}, \quad x(t) = \int_{0}^{t} v(\tau) d\tau \quad (\text{Area})
Moving cart synchronized with graphsValueTimePosition vs. Time (x-t)
Position (x)
36.00 m
Velocity (v)
12.00 m/s
Acceleration
1.50 m/s²

Free Fall

Free Fall Concepts

A classic example of constant 1D acceleration is an object falling under the sole influence of gravity near the Earth's surface. In this case, the acceleration is constant and directed downwards: a=g=9.81 m/s2a = -g = -9.81 \text{ m/s}^2 (assuming the positive y-axis points upward).

Note: In true free fall, the mass, size, and shape of the object do not affect its acceleration (neglecting air resistance).

2D Motion: Projectile Motion

2D Motion: Projectile Motion Concepts

When an object is launched into the air and moves in two dimensions under the influence of gravity alone, it is in projectile motion. A key assumption is that air resistance is negligible.

The fundamental principle for solving projectile motion problems is the independence of motion: the horizontal (xx) and vertical (yy) motions are completely independent of each other, except that they share the same elapsed time (tt).

Projectile Motion Principles

Horizontal Motion (x-axis):

Because gravity acts purely vertically, there is no horizontal acceleration.

  • Acceleration is zero (ax=0a_x = 0).
  • Velocity is constant (vx=vix=constantv_x = v_{ix} = \text{constant}).
  • Equation: Δx=vixt\Delta x = v_{ix} t

Vertical Motion (y-axis):

The vertical motion is identical to 1D free fall.

  • Acceleration is constant gravity (ay=ga_y = -g).
  • Velocity changes continuously.
  • Equations: The standard 1D kinematic equations apply, substituting yy for xx and g-g for aa.

Initial Velocity Components

If a projectile is launched from the origin with an initial velocity v0v_0 at an angle θ\theta above the horizontal, we must resolve the initial velocity into components:

Initial Horizontal Velocity

The initial horizontal component of the projectile's velocity.

vix=v0cosθv_{ix} = v_0 \cos\theta

Variables

SymbolDescriptionUnit
vixv_{ix}Initial horizontal velocitym/s
v0v_0Initial launch speedm/s
θ\thetaLaunch angle relative to horizontaldeg/rad

Initial Vertical Velocity

The initial vertical component of the projectile's velocity.

viy=v0sinθv_{iy} = v_0 \sin\theta

Variables

SymbolDescriptionUnit
viyv_{iy}Initial vertical velocitym/s
v0v_0Initial launch speedm/s
θ\thetaLaunch angle relative to horizontaldeg/rad

Interactive Simulation

Adjust launch conditions below to connect horizontal constant velocity with vertical free-fall acceleration.

Interactive Physics Simulation

Planetary Projectile Motion Simulator

Launch kinematics across different solar system gravity environments. Observe velocity vectors, peak trajectories, and launch mechanics.

25 m/s
40 deg
4.0 m
0.40
Planetary Ballistics Equations
Horizontal Motion (No Air Resistance):
x(t)=(v0cosθ)tx(t) = (v_0 \cos\theta) \cdot t
Vertical Kinematics with Planetary Gravity:
y(t)=h0+(v0sinθ)t12gt2y(t) = h_0 + (v_0 \sin\theta) \cdot t - \frac{1}{2}g t^2
Gravity (Earth): 9.81 m/s²
Horizontal Range (d)
67.19 m
Max Vertical Height
17.16 m
Flight Duration (t)
1.40 / 3.51 s

Key Projectile Characteristics

Maximum Height

Occurs when the vertical velocity vy=0v_y = 0.

Time of Flight

The total time the projectile is in the air. For a launch and landing at the same elevation, it is twice the time to reach maximum height.

Range (RR)

The horizontal distance covered. For a launch and landing at the same elevation, R=v02sin(2θ)gR = \frac{v_0^2 \sin(2\theta)}{g}. Maximum range is achieved at θ=45\theta = 45^\circ.

Key Projectile Characteristics Concepts

Understanding key projectile characteristics such as maximum height, time of flight, and range is crucial for analyzing 2D motion under gravity.

Circular Motion Acceleration

Circular Motion Acceleration Concepts

When an object moves along a curved path, its acceleration can be broken into two orthogonal components: tangential and normal (centripetal) acceleration.

Tangential Acceleration

The component of acceleration parallel to the velocity vector, changing the speed.

at=dvdta_t = \frac{dv}{dt}

Variables

SymbolDescriptionUnit
ata_tTangential accelerationm/s2m/s^2
vvMagnitude of velocity (speed)m/s
ttTimes

Centripetal (Normal) Acceleration

The component of acceleration perpendicular to velocity, changing the direction towards the center of curvature.

ac=v2ra_c = \frac{v^2}{r}

Variables

SymbolDescriptionUnit
aca_cCentripetal accelerationm/s2m/s^2
vvMagnitude of velocity (speed)m/s
rrRadius of curvaturem

Uniform Circular Motion

In uniform circular motion (constant speed), at=0a_t = 0, and the object only experiences centripetal acceleration. In transportation engineering, understanding this centripetal acceleration is critical when designing horizontal curves for highways and railways to ensure vehicles don't slip outward due to insufficient friction or banking.

Relative Motion

Relative Motion Concepts

Velocity is not absolute; it depends on the frame of reference of the observer. If you are sitting in a train moving at 50 m/s relative to the ground, your velocity relative to the train is zero, but your velocity relative to an observer on the platform is 50 m/s.

If object A is moving with velocity vAE\vec{v}_{AE} relative to Earth, and object B is moving with velocity vBE\vec{v}_{BE} relative to Earth, the velocity of object A relative to object B (vAB\vec{v}_{AB}) is:

1D Relative Velocity

Velocity of object A relative to object B.

vAB=vAEvBE\vec{v}_{AB} = \vec{v}_{AE} - \vec{v}_{BE}

Variables

SymbolDescriptionUnit
vAB\vec{v}_{AB}Velocity of A relative to Bm/s
vAE\vec{v}_{AE}Velocity of A relative to Earthm/s
vBE\vec{v}_{BE}Velocity of B relative to Earthm/s

Relative Motion Addition

Alternatively, the velocity of an object relative to a stationary frame (vP/E\vec{v}_{P/E}) is the sum of the velocity of the object relative to a moving frame (vP/M\vec{v}_{P/M}) and the velocity of the moving frame relative to the stationary frame (vM/E\vec{v}_{M/E}):

Relative Velocity Addition

Finding absolute velocity from relative velocity and moving frame velocity.

vP/E=vP/M+vM/E\vec{v}_{P/E} = \vec{v}_{P/M} + \vec{v}_{M/E}

Variables

SymbolDescriptionUnit
vP/E\vec{v}_{P/E}Velocity of P relative to Earthm/s
vP/M\vec{v}_{P/M}Velocity of P relative to moving frame Mm/s
vM/E\vec{v}_{M/E}Velocity of moving frame M relative to Earthm/s

Relative Velocity in 2D

Moving Reference Frames

While relative motion in 1D is simply vector addition or subtraction along a line, relative velocity in 2D requires vector algebra. This is essential for analyzing the motion of airplanes in crosswinds or boats crossing rivers with currents.

If vP/A\vec{v}_{P/A} is the velocity of object P relative to frame A, and vA/B\vec{v}_{A/B} is the velocity of frame A relative to frame B, then the velocity of object P relative to frame B is the vector sum:

2D Relative Velocity

Vector addition of relative velocities across different reference frames.

vP/B=vP/A+vA/B\vec{v}_{P/B} = \vec{v}_{P/A} + \vec{v}_{A/B}

Variables

SymbolDescriptionUnit
vP/B\vec{v}_{P/B}Velocity of P relative to Bm/s
vP/A\vec{v}_{P/A}Velocity of P relative to Am/s
vA/B\vec{v}_{A/B}Velocity of A relative to Bm/s

Applications

To solve these problems, engineers decompose the velocity vectors into their xx and yy components and solve them independently using the standard component method discussed in the previous section.

Key Takeaways
  • Kinematics describes motion without forces. Key quantities are position, displacement, velocity, and acceleration.
  • Distinguish between average (interval) and instantaneous (point in time) quantities. Derivatives and integrals link position, velocity, and acceleration.
  • The Kinematic Equations apply only when acceleration is constant.
  • For Free Fall, acceleration is constant (a=9.81 m/s2a = -9.81 \text{ m/s}^2). Mass is irrelevant.
  • Projectile Motion is analyzed by separating it into independent, constant-velocity horizontal motion and constant-acceleration vertical motion, linked only by time.
  • Relative velocity requires defining a reference frame and using vector addition/subtraction.