Experiment 6: Archimedes' Principle and Specific Gravity — Worked Examples

These examples use spring-balance readings as direct evidence of buoyancy and show how the loss of apparent weight leads to density and specific gravity.

Example 1: Buoyant force from apparent weight

A solid weighs 4.90 N4.90\,\text{N} in air and 4.10 N4.10\,\text{N} while fully submerged in water. Determine the buoyant force.

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Example 2: Specific gravity of a solid denser than water

Use the readings from Example 1 to determine the solid specific gravity.

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Example 3: Density from specific gravity

If water density is taken as 998.2 kg/m3998.2\,\text{kg/m}^3, estimate the density of the solid with SG=6.13SG=6.13.

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Example 4: Specific gravity of an unknown liquid

The same solid reads 4.90 N4.90\,\text{N} in air, 4.10 N4.10\,\text{N} in water, and 4.25 N4.25\,\text{N} in a test liquid. Determine the test-liquid specific gravity.

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Example 5: Displaced volume from buoyant force

The buoyant force in water is 0.80 N0.80\,\text{N}. Using ρw=998.2 kg/m3\rho_w=998.2\,\text{kg/m}^3 and g=9.80665 m/s2g=9.80665\,\text{m/s}^2, determine the displaced volume.

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Example 6: Fraction submerged for a floating object

A uniform object has density 700 kg/m3700\,\text{kg/m}^3 and floats in water of density 998.2 kg/m3998.2\,\text{kg/m}^3. What fraction of its volume is submerged?

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Example 7: Air bubbles and direction of specific-gravity error

The correct water reading for the solid is 4.10 N4.10\,\text{N}, but trapped air bubbles make the spring balance read 4.00 N4.00\,\text{N}. Compare the resulting specific-gravity estimate with the correct value.

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Example 8: Floating solid using an auxiliary sinker

A floating solid weighs Ws,air=1.20 NW_{s,air}=1.20\,\text{N}. The auxiliary sinker alone has apparent weight Wa,water=3.00 NW_{a,water}=3.00\,\text{N} in water. When the solid and sinker are fully submerged together, their apparent weight is Ws+a,water=2.60 NW_{s+a,water}=2.60\,\text{N}. Determine the solid specific gravity.

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