Combined Stresses

Learning Objectives

  • Calculate combined normal stresses due to axial forces and bending moments.
  • Determine the core (kern) of a section to ensure no tension under eccentric loading.
  • Build the 2D plane stress tensor from individual internal forces.
  • Use stress transformation equations and Mohr's Circle to find principal stresses.
  • Evaluate the absolute maximum shear stress using 3D Mohr's Circle.
  • Apply failure theories (Rankine, Tresca, Von Mises) to evaluate material yielding.

In real-world structures, members are rarely subjected to a single type of loading. Combined stresses occur when a structural member is subjected to multiple internal forces simultaneously, such as an axial load combined with a bending moment, or a bending moment combined with torsion. These individual stress components must be superimposed or transformed to evaluate the critical state of stress.

Axial and Flexural Combined Stresses

Combined Axial and Flexural Loads

When a member carries both an axial load (PP) and a bending moment (MM), the normal stresses are superimposed.

Combined Normal Stress

Superposition of axial and flexural stresses.

σ=±PA±MyI\sigma = \pm \frac{P}{A} \pm \frac{My}{I}

Variables

SymbolDescriptionUnit
σ\sigmaCombined normal stress at a given point.-
PPAxial force.-
AACross-sectional area.-
MMBending moment.-
yyDistance from the neutral axis to the point of interest.-
IIMoment of inertia of the cross-section.-
  • Axial Term (P/AP/A): Uniform across the section.
  • Flexural Term (My/IMy/I): Varies linearly, zero at centroid.

Sign Convention

  • Tension: Positive (+)
  • Compression: Negative (-)
  • Ensure signs are consistent when adding stresses.

Eccentric Axial Loads and the Core (Kern) of a Section

An eccentric axial load is a load applied parallel to the centroidal axis but offset by a distance (eccentricity, ee). This creates an equivalent system of an axial load (PP) acting at the centroid, plus a bending moment (M=P×eM = P \times e).

Core or Kern

The area around the centroid of a cross-section within which an eccentric compressive load must act to ensure that the entire section remains in compression (no tensile stress develops).

For materials that are strong in compression but weak or entirely unable to carry tension (like concrete, masonry, or soil under a foundation), it is crucial to ensure that the entire cross-section remains in compression.

To prevent any tensile stress from developing, the combined compressive stress (P/AP/A) must be greater than or equal to the maximum tensile flexural stress (Mc/IMc/I).

Core of a Section (No Tension)

Condition for preventing tensile stress under eccentric loading.

PA(Pe)cI\frac{P}{A} \ge \frac{(P \cdot e) \cdot c}{I}

Variables

SymbolDescriptionUnit
PPAxial force.-
AACross-sectional area.-
eeEccentricity of the load from the centroidal axis.-
ccDistance from neutral axis to the extreme fiber.-
IIMoment of inertia of the cross-section.-

By setting the edge stress to exactly zero, we can solve for the maximum allowable eccentricity (emaxe_{max}). The area defined by this maximum eccentricity in all directions around the centroid is called the Core or Kern. As long as the resultant compressive load acts within this core, the entire section will be under compression.

  • Rectangular Section (b×hb \times h): The core is a rhombus. For a load on the vertical axis, eh/6e \le h/6. This is the famous "Middle-Third Rule".
  • Solid Circular Section (diameter dd): The core is a circle with radius ed/8e \le d/8. This is the "Middle-Fourth Rule".

The General State of Stress (3D to 2D)

Plane Stress

A 2D stress condition where stresses on one face (usually the z-face) are zero. This simplifies most practical engineering problems like beams, shafts, and pressure vessels.

While structures exist in 3D space, most practical engineering problems can be simplified to a plane stress condition.

Building the Stress Tensor

When evaluating a critical point on a structural member, we must carefully sum all stresses acting on that point from every internal force:

  • Axial Force (PP): Normal Stress (σ=P/A\sigma = P/A)
  • Bending Moment (MM): Flexural Normal Stress (σ=My/I\sigma = My/I)
  • Shear Force (VV): Transverse Shear Stress (τ=VQ/Ib\tau = VQ/Ib)
  • Torsion (TT): Torsional Shear Stress (τ=Tρ/J\tau = T\rho/J)

These components are summed algebraically based on their direction to form the final stress state (σx,σy,τxy\sigma_x, \sigma_y, \tau_{xy}) for that specific point.

Stress Transformation and Mohr's Circle

State of Stress and Transformation

The stress at a point is defined by normal stresses (σx,σy\sigma_x, \sigma_y) and shear stress (τxy\tau_{xy}). To find stresses on an inclined plane or the maximum stresses, we use stress transformation equations.

Mohr's Circle

Mohr's Circle is a graphical method to represent the state of stress.

  • Center (CC): (σx+σy2,0)(\frac{\sigma_x + \sigma_y}{2}, 0)
  • Radius (RR): (σxσy2)2+τxy2\sqrt{(\frac{\sigma_x - \sigma_y}{2})^2 + \tau_{xy}^2}

Principal Stresses

The maximum and minimum normal stresses acting on an element, occurring on planes where shear stress is zero.

Principal Stresses (2D)

Formulas to compute the maximum and minimum normal stresses.

σ1,2=σx+σy2±R\sigma_{1,2} = \frac{\sigma_x + \sigma_y}{2} \pm R

Variables

SymbolDescriptionUnit
σ1,σ2\sigma_1, \sigma_2Principal stresses.-
σx,σy\sigma_x, \sigma_yNormal stresses on the x and y faces.-
RRRadius of Mohr's Circle.-

Maximum In-Plane Shear Stress

The absolute maximum shear stress in the defined plane is equal to the radius of the Mohr's Circle.

Maximum In-Plane Shear Stress

Maximum shear stress in the x-y plane.

τmax=R\tau_{max} = R

Variables

SymbolDescriptionUnit
τmax\tau_{max}Maximum in-plane shear stress.-
RRRadius of Mohr's Circle.-

3D Mohr's Circle

While plane stress problems (σz=0,τxz=τyz=0\sigma_z = 0, \tau_{xz} = \tau_{yz} = 0) are commonly solved using a single 2D Mohr's Circle, the true state of stress is triaxial. Even in plane stress, there are actually three principal stresses (σ1,σ2\sigma_1, \sigma_2, and σ3=0\sigma_3 = 0).

To evaluate the absolute maximum shear stress occurring in any plane (not just the x-y plane), a 3D Mohr's Circle must be constructed. This consists of three intersecting circles drawn between the three principal stresses:

  • Circle 1: Between σ1\sigma_1 and σ2\sigma_2 (the standard 2D in-plane circle).
  • Circle 2: Between σ2\sigma_2 and σ3\sigma_3 (which is 00 in plane stress).
  • Circle 3: Between σ1\sigma_1 and σ3\sigma_3 (which is 00 in plane stress).

The Absolute Maximum Shear Stress (τabs_max\tau_{abs\_max}) is the radius of the largest of these three circles.

Absolute Maximum Shear Stress

Maximum shear stress considering the 3D stress state.

τabs_max=σmaxσmin2\tau_{abs\_max} = \frac{\sigma_{max} - \sigma_{min}}{2}

Variables

SymbolDescriptionUnit
τabs_max\tau_{abs\_max}Absolute maximum shear stress.-
σmax\sigma_{max}Maximum principal stress from the 3D state.-
σmin\sigma_{min}Minimum principal stress from the 3D state.-

If the two in-plane principal stresses (σ1\sigma_1 and σ2\sigma_2) have the same sign (both positive or both negative), the largest circle will actually involve the out-of-plane principal stress σ3=0\sigma_3 = 0. In this case, τabs_max\tau_{abs\_max} will be greater than the in-plane τmax\tau_{max}. This distinction is critical for evaluating failure theories.

Failure Theories and Yield Criteria

Failure Theories for Ductile vs. Brittle Materials

After combining stresses and determining the principal stresses (σ1,σ2,σ3\sigma_1, \sigma_2, \sigma_3) using Mohr's Circle, the final step in structural design is predicting if the material will fail under this complex multiaxial stress state.

Different materials require different failure theories:

1. Maximum Principal Stress Theory (Rankine's Theory) Used for: Brittle materials (like concrete, cast iron, glass). The material fails when the maximum principal tensile stress reaches the ultimate tensile strength (σult\sigma_{ult}) from a simple tension test, regardless of the other principal stresses.

  • Fails if: σ1σult\sigma_1 \ge \sigma_{ult}

2. Maximum Shear Stress Theory (Tresca Criterion) Used for: Ductile materials (like mild steel). The material yields when the absolute maximum shear stress (τabs_max\tau_{abs\_max}) reaches the shear yield strength (τY\tau_Y) from a simple tension test (where τY=σY/2\tau_Y = \sigma_Y / 2).

  • Yields if: τabs_max=σ1σ32σY2\tau_{abs\_max} = \frac{|\sigma_1 - \sigma_3|}{2} \ge \frac{\sigma_Y}{2}

3. Maximum Distortion Energy Theory (Von Mises Criterion) Used for: Ductile materials (most accurate and widely used for metals). Yielding occurs when the distortion energy per unit volume equals or exceeds the distortion energy at yield in a simple tension test. The stresses are combined into an "equivalent" or "effective" Von Mises stress (σv\sigma_v):

  • Yields if: σvσY\sigma_v \ge \sigma_Y
  • Under plane stress (σ3=0\sigma_3 = 0), the formula is: σv=σ12σ1σ2+σ22\sigma_v = \sqrt{\sigma_1^2 - \sigma_1\sigma_2 + \sigma_2^2}

Interactive Tool: 2D Stress Element

Visualize how normal and shear stresses deform a rectangular element, and see how rotating the element changes the stress components acting on its faces. Finding the angle where shear stress becomes zero reveals the Principal Planes.

Interactive Simulation

Use the simulation below to explore how normal and shear stresses deform a rectangular element, and see how rotating the element changes the stress components.

Eccentrically Loaded Column Visualizer

Combine uniform axial compression with bending stress caused by an eccentric load.

P = 150 kN
e=50
Cross-section: 300mm × 200mm
Left edge (-150)Centroid (0)Right edge (+150)

Stress Distribution across Width (MPa)

Loading chart...
Axial
Bending
Combined
Stress at Left Face (y = -150)
0.00 MPa
(Compression)
Stress at Right Face (y = +150)
-5.00 MPa
(Compression)

Interactive Tool: Mohr's Circle

Input the stress state (σx,σy,τxy\sigma_x, \sigma_y, \tau_{xy}) to visualize the principal stresses and maximum shear stress using Mohr's Circle.

Interactive Simulation

Input the stress state (σx,σy,τxy\sigma_x, \sigma_y, \tau_{xy}) below to visualize the principal stresses and maximum shear stress using Mohr's Circle.

Mohr's Circle Interactive

Stress State Inputs (MPa)

80
-40
30
0°

Calculated Results

Center (C)
0.0
Radius (R)
0.0
Principal sigma1\\sigma_1
0.0
Principal sigma2\\sigma_2
0.0
Max Shear (taumax\\tau_{max})
0.0
στX (80, 30)Y (-40, -30)
0°
Key Takeaways
  • Superposition Principle: For linear elastic materials, stresses from different loads can be added algebraically (σ=±P/A±My/I\sigma = \pm P/A \pm My/I).
  • Core/Kern of a Section: For materials weak in tension, the resultant eccentric compressive load must act within the "middle-third" (or "middle-fourth" for circles) to ensure the entire section remains entirely in compression.
  • Principal Stresses: The maximum and minimum normal stresses acting on an element, occurring on planes where shear stress is zero.
  • Mohr's Circle: A visual tool for evaluating 2D stress transformation, identifying principal stresses (C±RC \pm R) and maximum in-plane shear stress (RR).
  • 3D Mohr's Circle and Absolute Max Shear: Even in plane stress, the out-of-plane stress (σ3=0\sigma_3 = 0) creates three principal circles. If σ1\sigma_1 and σ2\sigma_2 share the same sign, the absolute maximum shear stress acts on an out-of-plane plane and is larger than the 2D in-plane maximum.
  • Failure Theories: Once the combined principal stresses are found, they must be compared against material yield strengths using Rankine (Brittle), Tresca (Ductile, conservative), or Von Mises (Ductile, highly accurate) yield criteria.