Solved Problems

Problem 1: Covariance Calculation (Basic)

Two variables XX (Temperature, ^{\circ}C) and YY (Expansion, mm) have the following joint distribution:

  • (20, 1): P=0.2P=0.2
  • (30, 2): P=0.5P=0.5
  • (40, 3): P=0.3P=0.3

Calculate the covariance between Temperature and Expansion.

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Problem 2: Marginal Distributions (Intermediate)

A civil engineering firm evaluates two suppliers of steel rebars based on two criteria: Grade XX (1 for Standard, 2 for High Strength) and Delivery Time YY (1 for On-Time, 2 for Delayed). The joint probability distribution f(x,y)f(x, y) is given as a table:

  • f(1,1)=0.40f(1,1) = 0.40
  • f(1,2)=0.15f(1,2) = 0.15
  • f(2,1)=0.30f(2,1) = 0.30
  • f(2,2)=0.15f(2,2) = 0.15

Find the marginal distributions of Grade XX and Delivery Time YY, and determine if the two variables are independent.

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Problem 3: Conditional Probability (Discrete)

Using the joint probability distribution from Problem 2, find the conditional probability that the delivery is delayed (Y=2Y=2) given that the steel grade is High Strength (X=2X=2).

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Problem 4: Expected Value of a Sum (Linearity of Expectation)

The cost of materials for a project depends on the quantity of cement (XX, in tons) and the quantity of sand (YY, in tons). The expected quantities are E[X]=50E[X] = 50 tons and E[Y]=120E[Y] = 120 tons. The cost function is C=100X+20YC = 100X + 20Y. Calculate the expected total cost, E[C]E[C].

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Problem 5: Correlation Coefficient

Using the data from Problem 1, calculate the correlation coefficient between Temperature (XX) and Expansion (YY). The standard deviations are given as σX=7.746\sigma_X = 7.746 and σY=0.7000\sigma_Y = 0.7000.

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Problem 6: Continuous Joint Density Function (Advanced)

The joint probability density function of two continuous variables XX (wind speed, m/s) and YY (structural vibration amplitude, mm) is defined as:

f(x,y)=k(x+y) for 0x2, and 0y2f(x,y) = k(x+y) \text{ for } 0 \le x \le 2, \text{ and } 0 \le y \le 2

Determine the value of the constant kk that makes this a valid joint PDF.

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Problem 7: Marginal Density Function (Continuous)

Given the joint PDF from Problem 6, where k=1/8k = 1/8:

f(x,y)=18(x+y) for 0x2, and 0y2f(x,y) = \frac{1}{8}(x+y) \text{ for } 0 \le x \le 2, \text{ and } 0 \le y \le 2

Determine the marginal probability density function of wind speed, fX(x)f_X(x).

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Problem 8: Expected Value of a Function

Let XX and YY have the joint PDF from Problem 7:

f(x,y)=18(x+y) for 0x2, and 0y2f(x,y) = \frac{1}{8}(x+y) \text{ for } 0 \le x \le 2, \text{ and } 0 \le y \le 2

Find the expected value of the product XYXY, E[XY]E[XY].

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Problem 9: Probability of an Event for Continuous Variables

Using the joint PDF from Problem 7:

f(x,y)=18(x+y) for 0x2, and 0y2f(x,y) = \frac{1}{8}(x+y) \text{ for } 0 \le x \le 2, \text{ and } 0 \le y \le 2

Calculate the probability that the sum of wind speed and vibration amplitude is less than 1, i.e., P(X+Y<1)P(X + Y < 1).

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Problem 10: Evaluating a Joint Cumulative Distribution Function (CDF)

The joint CDF of two continuous random variables XX and YY is given by:

F(x,y)={(1e2x)(1e3y)for x0,y00otherwiseF(x,y) = \begin{cases} (1 - e^{-2x})(1 - e^{-3y}) & \text{for } x \ge 0, y \ge 0 \\ 0 & \text{otherwise} \end{cases}

Find the probability that X1X \le 1 and Y2Y \le 2, and derive the joint PDF f(x,y)f(x,y).

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Problem 11: Independence of Continuous Variables

Using the joint PDF derived in Problem 10:

f(x,y)=6e2x3y for x0,y0f(x,y) = 6e^{-2x - 3y} \text{ for } x \ge 0, y \ge 0

Determine if the variables XX and YY are independent.

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