Mechanical Vibrations

Learning Objectives

  • Understand the fundamentals of mechanical vibrations, including period, frequency, and amplitude.
  • Derive and apply equations of motion for free undamped vibrations.
  • Analyze torsional vibrations in rotational systems.
  • Evaluate the effects of damping on free vibrations, including overdamped, critically damped, and underdamped cases.
  • Apply the logarithmic decrement to measure damping experimentally.
  • Understand the behavior of systems under forced vibrations and the phenomenon of resonance.

Vibration is the periodic motion of a body or system of connected bodies displaced from a position of equilibrium.

Free Undamped Vibrations

Consider a block of mass mm attached to a spring of stiffness kk. For free vibration (no external force), the system undergoes simple harmonic motion, balancing the inertial force and restoring spring force.

Simple Harmonic Motion (SHM)

A type of periodic motion where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacement.

Free Undamped Equation of Motion

The differential equation governing free, undamped vibration and its simple harmonic solution.

mxΒ¨+kx=0m \ddot{x} + k x = 0x(t)=Asin⁑(Ο‰nt)+Bcos⁑(Ο‰nt)x(t) = A \sin(\omega_n t) + B \cos(\omega_n t)

Variables

SymbolDescriptionUnit
mmMass of the bodykg
kkSpring stiffnessN/m
xxDisplacement from equilibriumm
x¨\ddot{x}Accelerationm/s2m/s^2
A,BA, BConstants determined by initial conditionsm
Ο‰n\omega_nNatural circular frequencyrad/s
ttTimes

Amplitude

The maximum magnitude of displacement from the equilibrium position. It describes the "size" of the oscillation.

Natural Circular Frequency (Ο‰n\omega_n)

The rate of oscillation measured in radians per second. Ο‰n=km(rad/s)\omega_n = \sqrt{\frac{k}{m}} \quad (\text{rad/s})

Natural Frequency (fnf_n)

The number of complete cycles of oscillation per second. fn=Ο‰n2Ο€(Hz)f_n = \frac{\omega_n}{2\pi} \quad (\text{Hz})

Period (Ο„\tau)

The time required for one complete cycle of vibration. Ο„=1fn=2πωn=2Ο€mk(s)\tau = \frac{1}{f_n} = \frac{2\pi}{\omega_n} = 2\pi \sqrt{\frac{m}{k}} \quad (\text{s})

Analyzing Free Undamped Vibrations

  1. Define the Coordinate: Establish a coordinate system indicating the displacement xx from the static equilibrium position.
  2. Draw the Free-Body Diagram: Draw the body in a displaced position and identify all active restoring forces (like spring forces).
  3. Apply Newton's Second Law: Write the equation of motion βˆ‘Fx=mxΒ¨\sum F_x = m \ddot{x} or βˆ‘M=IΞΈΒ¨\sum M = I \ddot{\theta}.
  4. Identify Natural Frequency: Rearrange the equation into the standard form x¨+ωn2x=0\ddot{x} + \omega_n^2 x = 0 to identify ωn2\omega_n^2.
  5. Calculate Parameters: Use Ο‰n\omega_n to calculate the frequency fnf_n and period Ο„\tau.
  6. Apply Initial Conditions: Use initial displacement x(0)x(0) and velocity xΛ™(0)\dot{x}(0) to determine the constants AA and BB in the general solution.

Interactive Simulation

Interact with the simulation below to explore mechanical vibrations, varying mass and stiffness to observe changes in frequency and period.

Mechanical Vibrations β€” Mass-Spring-Damper SystemUnderdamped (ΞΆ = 0.06)

System Parameters

Vibration Equations

Equation of Motion:
mx¨+cx˙+kx=0m\ddot{x} + c\dot{x} + kx = 0
Ο‰n=km=3.16 rad/s\omega_n = \sqrt{\frac{k}{m}} = 3.16\,\text{rad/s}
ΞΆ=ccc=c2km=0.063\zeta = \frac{c}{c_c} = \frac{c}{2\sqrt{km}} = 0.063
Ο‰d=Ο‰n1βˆ’ΞΆ2=3.16 rad/s\omega_d = \omega_n\sqrt{1-\zeta^2} = 3.16\,\text{rad/s}
x(t):1.0000 m
αΊ‹(t):-0.0250 m/s
ẍ(t):-4.993 m/s²
t:0.00 s
Mechanical Vibration Model and Responsekceq.m+1.00mt(s)x(m)036912-1.00.01.0UnderdampedModelResponse x(t)

Simple Pendulum

For small angles (sinβ‘ΞΈβ‰ˆΞΈ\sin \theta \approx \theta), a simple pendulum behaves like a spring-mass system. The restoring force is provided by the component of gravity acting perpendicular to the pendulum string.

Pendulum Formulas

The natural frequency and period for a simple pendulum. Notice that they are independent of mass.

Ο‰n=gL\omega_n = \sqrt{\frac{g}{L}}Ο„=2Ο€Lg\tau = 2\pi \sqrt{\frac{L}{g}}

Variables

SymbolDescriptionUnit
Ο‰n\omega_nNatural frequencyrad/s
Ο„\tauPeriods
ggAcceleration due to gravitym/s2m/s^2
LLLength of the pendulum stringm

Interactive Simulation

Interact with the simulation below to explore simple pendulum motion. Observe how the period is independent of mass but dependent on length.

Simple Pendulum β€” Exact Numerical Integration

Pendulum Setup

Dynamics Equations

Equation of Motion:
θ¨+gLsin⁑θ=0\ddot{\theta} + \frac{g}{L}\sin\theta = 0
Small-Angle Period:
T=2Ο€Lg=2.457 sT = 2\pi\sqrt{\frac{L}{g}} = 2.457\,\text{s}
ΞΈ (current):30.0Β°
Ο‰\omega:0.000 rad/s
TT (current):0.00 s
Normal (NN):16.99 N
Pendulum Motion Workspacem30.0Β°Method: RK4 integration (exact for large ΞΈ)
Energy Balance
PE3.94 J
KE0.00 J
Total Eβ‚€3.94 J
Phase Portrait (ΞΈ, Ο‰)Phase portraitΞΈΟ‰

Torsional Vibrations

Vibrations can also occur in rotational systems. The angular equivalent to a spring is a torsional spring (e.g., a twisting shaft), which provides a restoring torque MtM_t proportional to the angle of twist ΞΈ\theta.

Torsional Vibration Equation

For a disk with mass moment of inertia I0I_0 attached to a torsional spring, the equation of motion is derived from βˆ‘MO=IOΞΈΒ¨\sum M_O = I_O \ddot{\theta}, yielding the standard form of the torsional vibration equation.

Torsional Vibration Formulas

The restoring torque, equation of motion, and natural circular frequency for torsional vibration.

Mt=βˆ’ktΞΈM_t = -k_t \thetaI0ΞΈΒ¨+ktΞΈ=0I_0 \ddot{\theta} + k_t \theta = 0Ο‰n=ktI0\omega_n = \sqrt{\frac{k_t}{I_0}}

Variables

SymbolDescriptionUnit
MtM_tRestoring torqueNβ‹…mN\cdot m
ktk_tTorsional stiffnessNβ‹…m/radN\cdot m/rad
ΞΈ\thetaAngle of twistrad
ΞΈΒ¨\ddot{\theta}Angular accelerationrad/s2rad/s^2
I0I_0Mass moment of inertiakgβ‹…m2kg\cdot m^2
Ο‰n\omega_nNatural circular frequencyrad/s

Damped Free Vibrations

In real systems, energy is dissipated through mechanisms like friction or fluid resistance, called damping. If a viscous damper (cc) is added to the system, the equation of motion must include a damping force proportional to velocity.

Damped Free Vibration Equation

Equation of motion for a system with mass, stiffness, and viscous damping.

mx¨+cx˙+kx=0m \ddot{x} + c \dot{x} + k x = 0

Variables

SymbolDescriptionUnit
mmMasskg
x¨\ddot{x}Accelerationm/s2m/s^2
ccViscous damping coefficientNβ‹…s/mN\cdot s/m
xΛ™\dot{x}Velocitym/s
kkSpring stiffnessN/m
xxDisplacementm

Critical Damping Coefficient (ccc_c)

The minimum amount of damping required to return a displaced system to equilibrium without oscillation. cc=2mωn=2kmc_c = 2m\omega_n = 2\sqrt{km}

Damping Ratio (ΞΆ\zeta)

A dimensionless measure of the actual damping in a system compared to the critical damping. ΞΆ=ccc\zeta = \frac{c}{c_c}

System Behavior Based on Damping Ratio

The damping ratio determines the nature of the system's response:

  • Underdamped (ΞΆ<1\zeta \lt 1): The system oscillates, but the amplitude exponentially decays over time. The frequency of this damped oscillation is Ο‰d=Ο‰n1βˆ’ΞΆ2\omega_d = \omega_n \sqrt{1 - \zeta^2}.
  • Critically Damped (ΞΆ=1\zeta = 1): The system returns to equilibrium as quickly as possible without oscillating.
  • Overdamped (ΞΆ>1\zeta \gt 1): The system returns to equilibrium slowly without oscillating. The greater the damping, the slower the return.

Logarithmic Decrement

For an underdamped system (ΞΆ<1\zeta \lt 1), the amplitude of oscillation decays exponentially. A practical way to measure the damping ratio experimentally is by comparing successive peak amplitudes.

Logarithmic Decrement

Calculates the logarithmic decrement, defined as the natural logarithm of the ratio of two successive peak amplitudes.

Ξ΄=ln⁑(x1x2)=2π΢1βˆ’ΞΆ2\delta = \ln\left(\frac{x_1}{x_2}\right) = \frac{2\pi \zeta}{\sqrt{1 - \zeta^2}}Ξ΄=1nln⁑(x0xn)\delta = \frac{1}{n} \ln\left(\frac{x_0}{x_n}\right)

Variables

SymbolDescriptionUnit
Ξ΄\deltaLogarithmic decrement-
x1,x2x_1, x_2Two successive peak amplitudes separated by one full cyclem
ΞΆ\zetaDamping ratio-
nnNumber of cycles-
x0x_0Initial peak amplitudem
xnx_nPeak amplitude after n cyclesm

Small Damping Approximation

For very small damping (ΞΆβ‰ͺ1\zeta \ll 1), the logarithmic decrement equation simplifies to Ξ΄β‰ˆ2π΢\delta \approx 2\pi \zeta.

Forced Vibrations

When a vibrating system is subjected to a continuous external periodic force, it undergoes forced vibration. Let the driving force be F(t)=F0sin⁑(Ο‰0t)F(t) = F_0 \sin(\omega_0 t), where Ο‰0\omega_0 is the driving frequency.

Forced Undamped Vibration

Equation of motion and steady-state solution amplitude for forced undamped vibration.

mxΒ¨+kx=F0sin⁑(Ο‰0t)m \ddot{x} + k x = F_0 \sin(\omega_0 t)xp(t)=Xsin⁑(Ο‰0t)x_p(t) = X \sin(\omega_0 t)X=F0kβˆ’mΟ‰02=F0/k1βˆ’(Ο‰0/Ο‰n)2X = \frac{F_0}{k - m\omega_0^2} = \frac{F_0/k}{1 - (\omega_0/\omega_n)^2}

Variables

SymbolDescriptionUnit
xp(t)x_p(t)Steady-state solution displacementm
mmMasskg
x¨\ddot{x}Accelerationm/s2m/s^2
kkSpring stiffnessN/m
xxDisplacementm
F0F_0Amplitude of the driving forceN
Ο‰0\omega_0Driving frequencyrad/s
ttTimes
XXAmplitude of the steady-state solutionm
Ο‰n\omega_nNatural circular frequencyrad/s

Magnification Factor (MF)

The ratio of the dynamic amplitude to the static deflection.

MF=XF0/k=1∣1βˆ’(Ο‰0/Ο‰n)2∣MF = \frac{X}{F_0/k} = \frac{1}{|1 - (\omega_0/\omega_n)^2|}

Variables

SymbolDescriptionUnit
MFMFMagnification factor-
XXDynamic amplitudem
F0F_0Amplitude of the driving forceN
kkSpring stiffnessN/m
Ο‰0\omega_0Driving frequencyrad/s
Ο‰n\omega_nNatural circular frequencyrad/s

Resonance Caution

When the driving frequency Ο‰0\omega_0 exactly equals the natural frequency Ο‰n\omega_n, Resonance occurs. The amplitude theoretically goes to infinity (if undamped). In physical structures like bridges or buildings, this condition can cause severe, catastrophic structural damage.

Key Takeaways
  • Free Vibration (mxΒ¨+kx=0m\ddot{x} + kx = 0) occurs without external forces and results in simple harmonic motion.
  • Natural Frequency (Ο‰n=k/m\omega_n = \sqrt{k / m}) depends only on the system's mass and stiffness.
  • Torsional Vibration follows the same principles, replacing mass with mass moment of inertia (I0I_0) and linear stiffness with torsional stiffness (ktk_t).
  • Period: Ο„=2Ο€/Ο‰n\tau = 2\pi/\omega_n
  • Damping (cc) dissipates energy, usually via fluid resistance or friction, and causes amplitude decay.
  • Logarithmic Decrement (Ξ΄\delta) is used to experimentally measure damping from the decay of successive amplitude peaks.
  • Critical Damping (ccc_c) defines the boundary between oscillatory and non-oscillatory motion.
  • Resonance occurs in forced vibration when driving frequency equals natural frequency, causing mathematically unbounded (and practically destructive) amplitude.