Kinetics of Particles: Impulse and Momentum

Learning Objectives

  • Understand the principles of linear impulse and momentum.
  • Apply the impulse-momentum equation to single particles and systems of particles.
  • Analyze conservation of linear and angular momentum.
  • Solve impact and collision problems using the coefficient of restitution.

The principle of impulse and momentum is an alternative method to Newton's Second Law for solving kinetics problems. It is particularly useful when the problem involves forces acting over a specific interval of time, or when dealing with impulsive forces (very large forces acting over a very short time, such as impacts).

Linear Momentum

A vector quantity (L=mv\mathbf{L} = m\mathbf{v}) that characterizes the motion of a mass. Its direction is the same as the velocity.

Linear Impulse

A vector quantity (I=∫Fdt\mathbf{I} = \int \mathbf{F} dt) representing the effect of a force acting over a period of time. For a constant force, I=F(t2−t1)\mathbf{I} = \mathbf{F}(t_2 - t_1).

Principle of Linear Impulse and Momentum

Integrating Newton's Second Law (∑F=mdvdt\sum \mathbf{F} = m \frac{d\mathbf{v}}{dt}) with respect to time yields the principle of linear impulse and momentum.

Linear Impulse and Momentum Principle

The principle states that the initial momentum of a particle at time t1t_1 plus the sum of all impulses applied from t1t_1 to t2t_2 equals the final momentum of the particle at time t2t_2.

Linear Impulse and Momentum Equation

Relates initial momentum, applied linear impulse, and final momentum of a particle.

mv1+∑∫t1t2Fdt=mv2m\mathbf{v}_1 + \sum \int_{t_1}^{t_2} \mathbf{F} dt = m\mathbf{v}_2

Variables

SymbolDescriptionUnit
mv1m\mathbf{v}_1Initial linear momentum vector of the particle at time t_1N·s
∑∫Fdt\sum \int \mathbf{F} dtLinear impulse vector of all external forces acting from t_1 to t_2N·s
mv2m\mathbf{v}_2Final linear momentum vector of the particle at time t_2N·s

Vector Resolution of Impulse-Momentum

The impulse-momentum equation is a vector equation, meaning it can be resolved into independent scalar components (e.g., xx, yy, zz directions).

Angular Momentum

The angular momentum HO\mathbf{H}_O of a particle about point OO is defined as the moment of its linear momentum: HO=r×mv\mathbf{H}_O = \mathbf{r} \times m\mathbf{v}.

Angular Impulse and Momentum for Particles

In addition to linear impulse and momentum, the principle can be extended to moments about a fixed point OO. This is specifically critical for analyzing central force motion where the moment of the central force about the origin is identically zero.

Angular Impulse and Momentum Equation

Relates initial angular momentum, applied angular impulse, and final angular momentum about point O.

(HO)1+∑∫t1t2MO dt=(HO)2(\mathbf{H}_O)_1 + \sum \int_{t_1}^{t_2} \mathbf{M}_O \, dt = (\mathbf{H}_O)_2

Variables

SymbolDescriptionUnit
(HO)1(\mathbf{H}_O)_1Initial angular momentum vector at t_1N·m·s
∑∫MO dt\sum \int \mathbf{M}_O \, dtSum of angular impulses of external moments about point ON·m·s
(HO)2(\mathbf{H}_O)_2Final angular momentum vector at t_2N·m·s

Conservation of Angular Momentum

If the resultant moment about point OO is zero (such as in orbital motion under the influence of gravity alone), the angular momentum about OO is conserved:

(HO)1=(HO)2(\mathbf{H}_O)_1 = (\mathbf{H}_O)_2

This directly implies r1mvθ1=r2mvθ2r_1 m v_{\theta1} = r_2 m v_{\theta2}, which is Kepler's Second Law.

System of Particles

The principle of impulse and momentum can be extended to a system of particles. For a system of nn particles, the internal forces (forces acting between particles) occur in equal and opposite collinear pairs due to Newton's Third Law. The sum of their impulses over any time interval is zero. Therefore, only external forces change the total momentum of the system.

Total Linear Momentum of a System

Expresses the total linear momentum in terms of total mass and the velocity of its mass center.

∑mivi=mvG\sum m_i \mathbf{v}_i = m\mathbf{v}_G

Variables

SymbolDescriptionUnit
mim_iMass of an individual particlekg
vi\mathbf{v}_iVelocity of an individual particlem/s
mmTotal mass of the systemkg
vG\mathbf{v}_GVelocity of the mass centerm/s

Motion of the Mass Center

Applying the impulse-momentum principle to the mass center demonstrates that a system of particles moves such that its mass center acts as if all mass is concentrated there, and all external forces act on it. This is a foundational bridge to Rigid Body Kinetics.

Impulse and Momentum of the Mass Center

Applies the impulse and momentum principle to the center of mass of a system.

m(vG)1+∑∫t1t2Fextdt=m(vG)2m(\mathbf{v}_G)_1 + \sum \int_{t_1}^{t_2} \mathbf{F}_{ext} dt = m(\mathbf{v}_G)_2

Variables

SymbolDescriptionUnit
m(vG)1m(\mathbf{v}_G)_1Initial momentum of the mass centerN·s
∑∫Fextdt\sum \int \mathbf{F}_{ext} dtSum of external impulsesN·s
m(vG)2m(\mathbf{v}_G)_2Final momentum of the mass centerN·s

Solving Impulse and Momentum Problems

  1. Identify the System: Determine if the problem involves a single particle or a system of interacting particles.
  2. Draw Momentum and Impulse Diagrams: Sketch the initial momentum vectors, the impulse vectors of all external forces, and the final momentum vectors.
  3. Establish a Coordinate System: Choose axes to resolve the vector impulse-momentum equation into scalar components.
  4. Apply Equations: Use mv1+∑∫Fdt=mv2m\mathbf{v}_1 + \sum \int \mathbf{F} dt = m\mathbf{v}_2 for each component direction.
  5. Check for Conservation: If external impulses in any direction are zero or negligible, apply the conservation of linear momentum equation for that direction.

Conservation of Linear Momentum

If the sum of the external impulses acting on a system of particles is zero, the total linear momentum of the system is conserved (remains constant).

Conservation Applications

This principle is most frequently applied to problems involving impacts or collisions between two or more bodies, where the impulsive forces of interaction are internal to the system and external impulses (like gravity during a very short impact time) are negligible.

Conservation of Linear Momentum Equation

States that the initial sum of momenta equals the final sum of momenta when no external impulses act.

∑mi(vi)1=∑mi(vi)2\sum m_i (\mathbf{v}_i)_1 = \sum m_i (\mathbf{v}_i)_2

Variables

SymbolDescriptionUnit
mim_iMass of particle ikg
(vi)1(\mathbf{v}_i)_1Initial velocity of particle im/s
(vi)2(\mathbf{v}_i)_2Final velocity of particle im/s

Interactive Simulation

Interact with the simulation below to explore collision and conservation of momentum.

Collision Impulse & Momentum Simulator

State: approaching

Collision Settings

Object A (Blue)
Mass (m1m_1)3.0 kg
Initial Velocity (v1v_1)3.0 m/s
Object B (Red)
Mass (m2m_2)2.0 kg
Initial Velocity (v2v_2)-2.0 m/s
Restitution (ee)0.70

Step-by-Step Solver

1. Momentum Conservation
m1v1+m2v2=m1v1′+m2v2′m_1 v_1 + m_2 v_2 = m_1 v_1' + m_2 v_2'
3 × 3.0 + 2 × -2.0 = 5.00 N·s
2. Restitution Relation
e(v1−v2)=v2′−v1′e(v_1 - v_2) = v_2' - v_1'
0.70 × (3.0 - (-2.0)) = 3.50 m/s
3. Solved Final Velocities
v1′=m1v1+m2v2−m2e(v1−v2)m1+m2v_1' = \frac{m_1 v_1 + m_2 v_2 - m_2 e(v_1 - v_2)}{m_1 + m_2}
v_1' = -0.40 m/s
v2′=v1′+e(v1−v2)v_2' = v_1' + e(v_1 - v_2)
v_2' = 3.10 m/s
Collision Space and PlotsCoMA3.0kgB2.0kg3.0 m/s-2.0 m/sx (pos)t (time)
Momentum Balance (Ns)
Initial Momentum:5.00
Final Momentum:5.00
Conservation verified: 100% constant
Energy Balance (Joules)
Initial KE:17.50 J
Final KE:9.85 J
Thermal Loss:7.65 J

Impact

Impact occurs when two bodies collide over a very short time interval, generating relatively large internal forces.

Impulsive vs. Non-Impulsive Forces

During an impact (a very short time interval Δt\Delta t), the extremely large forces generated between the colliding bodies are called impulsive forces. Their impulse ∫Fdt\int \mathbf{F} dt is significant.

Conversely, finite forces like weight (gravity) or small spring forces are non-impulsive forces. Because Δt≈0\Delta t \approx 0, their resulting impulse is negligible (∫Wdt≈0\int W dt \approx 0). Therefore, you can typically neglect gravity and similar forces during the instant of impact when setting up the momentum conservation equations.

Impact

Types of Impact

Coefficient of Restitution (e)

A measure of the capacity of the colliding bodies to recover their shape after deformation. It is defined as the ratio of the relative velocity of separation to the relative velocity of approach along the line of impact.

Coefficient of Restitution Equation

Calculates the coefficient of restitution from velocities along the line of impact.

e=(vB)2−(vA)2(vA)1−(vB)1e = \frac{(v_B)_2 - (v_A)_2}{(v_A)_1 - (v_B)_1}

Variables

SymbolDescriptionUnit
eeCoefficient of restitutionunitless
(vA)1,(vB)1(v_A)_1, (v_B)_1Initial velocities of bodies A and B along the line of impactm/s
(vA)2,(vB)2(v_A)_2, (v_B)_2Final velocities of bodies A and B along the line of impactm/s

Elasticity in Impact

Interactive Simulation

Interact with the simulation below to explore the coefficient of restitution.

Coefficient of Restitution Simulator

e: 0.75 | h_0: 4.0 m

Simulation Settings

Restitution Coeff (ee)0.75
Release Height (h0)4.0 m

Mathematical Derivation

Coefficient of Restitution
e=−v+v−e = -\frac{v^+}{v^-}
Waiting for first bounce...
Peak Height Decay
hnext=e2hprevh_{next} = e^2 h_{prev}
Initial Height: h0=4.00 mh_0 = 4.00 \text{ m}
Current Bounces: 0
Next Max Height: h1=4.00 mh_{1} = 4.00 \text{ m}
Coefficient of Restitution System0m1m2m3m4m5mRelease (h0 = 4.0m)4.00mHeight (m)Time (s)0s2s4s6s8s
Current Time0.00 s
Height (y)4.00 m
Velocity (v)0.00 m/s
Key Takeaways
  • Impulse and Momentum Principle relates forces, mass, velocities, and time directly.
  • Linear Momentum (mvm\mathbf{v}) is the "quantity of motion."
  • Linear Impulse (∫Fdt\int \mathbf{F} dt) is the effect of a force over a time interval.
  • System of Particles: The mass center acts as a single particle with mass mm experiencing the net external impulse.
  • Conservation of Momentum occurs when net external impulses are zero, commonly used in collision problems.
  • Coefficient of Restitution (ee) defines the elasticity of an impact, ranging from 0 (plastic) to 1 (elastic).