Module 2 Worked Examples: Timber Tension and Compression Members

These examples use the revised NSCP timber workflow: timber-specific critical sections, bearing, effective length, Euler stress, and the unified column-stability factor.

Worked-example data provenance

Unless an example explicitly cites a code table, manufacturer report, or material specification, numerical material properties and adjustment factors are problem-supplied inputs. They demonstrate the calculation procedure and must not be reused as universal NSCP design values for another species, grade, steel grade, section, or product.

Example 1 — Axial tension stress in a clear section

A timber tie carries P=72 kNP=72\text{ kN} through a clear section measuring 100 mm×180 mm100\text{ mm}\times180\text{ mm}. Determine the axial tension stress.

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Example 2 — Timber net section with a projected bolt-hole deduction

A 120 mm120\text{ mm} wide by 50 mm50\text{ mm} thick timber plate has one 22 mm22\text{ mm} diameter hole crossing the critical section. Determine the simple projected net area used for the section check.

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Connection-region scope

A real multi-fastener timber connection also requires the NSCP Section 619 checks for spacing, end/edge distance, row or group tear-out, splitting, and fastener resistance. The projected-area calculation alone does not establish connection capacity.

Example 3 — Bearing perpendicular to grain

A beam reaction of 36 kN36\text{ kN} is carried by a 100 mm100\text{ mm} wide seat with a 120 mm120\text{ mm} bearing length. Determine the average bearing stress.

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Example 4 — Column slenderness about both axes

A rectangular timber post is 150 mm×250 mm150\text{ mm}\times250\text{ mm}, 3.0 m3.0\text{ m} long, and has K=1.0K=1.0. Determine KL/dKL/d about both section dimensions.

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Example 5 — Euler reference stress for a timber column

For a column with governing Le/d=20L_e/d=20 and Emin⁡′=4,000 MPaE_{\min}'=4{,}000\text{ MPa}, calculate FcEF_{cE}.

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Example 6 — Column stability factor for sawn lumber

Use Fc∗=12.0 MPaF_c^*=12.0\text{ MPa}, FcE=8.22 MPaF_{cE}=8.22\text{ MPa}, and c=0.80c=0.80. Determine CPC_P and Fc′F_c'.

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Example 7 — Axial column capacity from the adjusted compression value

A 150 mm×250 mm150\text{ mm}\times250\text{ mm} post has Fc′=6.60 MPaF_c'=6.60\text{ MPa}. Determine the axial resistance corresponding to the stress check.

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Example 8 — Effect of increased effective length

Keep d=150 mmd=150\text{ mm} and K=1.0K=1.0, but increase the unsupported length from 3.0 m3.0\text{ m} to 4.5 m4.5\text{ m}. Compare slenderness.

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Example 9 — Architectural column proportion choice

Two equal-area conceptual posts are available: 150×300 mm150\times300\text{ mm} and 200×225 mm200\times225\text{ mm}. With the same KK and LL, identify which has the smaller governing KL/dKL/d.

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Example 10 — Connection-region design review

A timber tie passes the clear-section tension check but uses a short two-row bolted end connection close to the member end. Identify the additional checks required before approval.

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Example 11 — End-condition sensitivity and product constant selection

A 150 mm×250 mm150\text{ mm}\times250\text{ mm} sawn-lumber column is 3.0 m3.0\text{ m} long. Use Emin′=4,000 MPaE_{min}'=4{,}000\text{ MPa} and Fc∗=12 MPaF_c^*=12\text{ MPa}. Compare the weak-direction stability result using the NDS Appendix G recommended design KeK_e values for commonly approximated ideal end conditions. For sawn lumber use c=0.80c=0.80.

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